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iris [78.8K]
3 years ago
13

Which of the following whole numbers is even?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0
The answer is B. 936
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When solving the equation, which is the best first step to begin to simplify the equation?
boyakko [2]

Answer:

<h3>Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)</h3>

Step-by-step explanation:

Given the expression

- 2 (x + 3) = - 10

The first step in solving the expression is to multiply both sides by -1/2 as shown;

-1/2(-2)(x+3) = -1/2(-10)

(x +3) = 1/2(10)

x + 3 = 5

x = 5-3

x = 2

Hence the correct option is Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)

6 0
2 years ago
Read 2 more answers
Solve using elimination.<br> 5x + 7y = -6<br> 4x + 7y = -9
Ede4ka [16]
Answer:

Simplifying
5x + 7y = -6

Solving
5x + 7y = -6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7y' to each side of the equation.
5x + 7y + -7y = -6 + -7y

Combine like terms: 7y + -7y = 0
5x + 0 = -6 + -7y
5x = -6 + -7y

Divide each side by '5'.
x = -1.2 + -1.4y

Simplifying
x = -1.2 + -1.4y
__________________________________

Simplifying
4x + 7y = -9

Solving
4x + 7y = -9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7y' to each side of the equation.
4x + 7y + -7y = -9 + -7y

Combine like terms: 7y + -7y = 0
4x + 0 = -9 + -7y
4x = -9 + -7y

Divide each side by '4'.
x = -2.25 + -1.75y

Simplifying
x = -2.25 + -1.75y
6 0
3 years ago
Please help me!!!!!!!!!!!!!!!!!!!!!!!!
mihalych1998 [28]

Answer:

sorry dont know

Step-by-step explanation:

6 0
2 years ago
Derivative of cos(4x)
son4ous [18]
D/dx ( cos (4x)) = - sin (4x) · d/dx ( 4x) = - 4 sin (4x) 
7 0
3 years ago
Adult tickets to the fall play cost $8 and student tickets cost $4. The drama class sold 30 more adult tickets than student tick
Arada [10]
8a+4s=840
a=s+30
8(s+30)+4s=840
12s+240=840
12s=600
s=50

A=s+30
a=50+30
a=80

The drama play sold 80 adult tickets
8 0
3 years ago
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