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Lady bird [3.3K]
3 years ago
7

Potassium sulfate has a solubility of 15 g/100 g water at 40°C. A solution is prepared by adding 47 g of potassium sulfate to 15

0 g of water, carefully heating the solution, and cooling it to 40°C. A homogeneous solution is obtained. Answer the following questions to determine whether the solution is saturated, unsaturated, or supersaturated. How many grams of potassium sulfate would dissolve in 100 g of water to make a saturated solution?
Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
4 0
The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:

[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.

So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.

To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.
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dolphi86 [110]
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
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V =  \frac{35}{102.27}
\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark
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