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marshall27 [118]
3 years ago
7

Can sound pass through space?

Chemistry
2 answers:
Tresset [83]3 years ago
6 0

Answer:

no it can not

Explanation:

-BARSIC- [3]3 years ago
4 0

Answer:

No they cannot Travel through space.

Explanation:

There are not atoms or molecules to vibrate.

Hope this helps <3

You might be interested in
Convert 167.9mL to daL.
juin [17]

Answer:

0.01679

Explanation:

1 ml = 0.0001 dal

167.9×0.0001 = 0.01679

3 0
4 years ago
Which statement best describes how energy is important to chemistry?
nordsb [41]

Answer:

C. Energy is absorbed and released during chemical reactions,

Explanation:

All chemical reactions involve energy. Energy is used to break bonds in reactants, and energy is released when new bonds form in products. Endothermic reactions absorb energy, and exothermic reactions release energy.

7 0
3 years ago
Read 2 more answers
Identify the molecule with the highest boiling point. NH3 CO2 C2H2 C3H8
Black_prince [1.1K]

Answer:

NH3

Explanation:

NH3 molecules make strong intermolecular H bondings and also because of the increase in the size of atomic radius.

4 0
4 years ago
A 1.0 L buffer solution is 0.300 M HC2H3O2 and 0.045 M LiC2H3O2. Which of the following actions will destroy the buffer?
zheka24 [161]

Answer:

b) Adding 0.075 moles of HCl

Explanation:

A buffer is defined as the aqueous mixture of a weak acid and its conjugate base or vice versa (Weak base with its conjugate acid).

The buffer of the problem is the acetic acid / lithium acetate.

The addition of any moles of the acid and the conjugate base will not destroy the buffer, just would change the pH of the buffer. Thus, a and c will not destroy the buffer.

The addition of an acid (HCl) or a base (NaOH), produce the following reactions:

HCl + LiC₂H₃O₂ → HC₂H₃O₂ + LiCl

<em>The acid reacts with the conjugate base to produce the weak acid.</em>

<em />

And:

NaOH + HC₂H₃O₂  →NaC₂H₃O₂ + H₂O

<em>The base reacts with the weak acid to produce conjugate base.</em>

<em />

As the buffer is 1.0L, the moles of the species of the buffer are:

HC₂H₃O₂ = 0.300 moles

LiC₂H₃O₂ = 0.045 moles

The reaction of HCl with LiC₂H₃O₂ consume all LiC₂H₃O₂ -<em>because there are an excess of moles of HCl that react with all </em>LiC₂H₃O₂-

As you will have just HC₂H₃O₂ after the reaction, the addition of b destroy the buffer.

In the other way, 0.0500 moles of NaOH react with the HC₂H₃O₂ but not consuming all HC₂H₃O₂, thus d doesn't destroy the buffer.

5 0
4 years ago
Can someone please help me with this? This is due today, please please help me!
Elanso [62]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>

ATOMIC NUMBER: It is the number of protons present in the nucleus of every atom

MASS NUMBER: It is the number of nucleon. Nucleon are the number of proton and neutrons present in the nucleus.

PROTON NUMBER: Proton number equal to the atomic number.

ELECTRON NUMBER: Electron Number is equal to the atomic number.

NEUTRON NUMBER: It is Mass Number - Atomic Number.

CHARGE: It is due to the addition or removal of the electron. + charge when electron removed and - charge when electron is added.

SYMBOL: It is represented as,

                                                X^Z_A

Z is Mass Number

A is Atomic Number

<h2>_____________________________________</h2><h2>Worksheet:</h2>

(I) ATOMIC NUMBER: 17

    MASS NUMBER: 35.5

    PROTON NUMBER: 17

    ELECTRON NUMBER: 17

    NEUTRON NUMBER: 18.5

    CHARGE: 0

<h2>_____________________________________</h2>

(II) ATOMIC NUMBER: 71

    MASS NUMBER: 180

    PROTON NUMBER: 71

    ELECTRON NUMBER: 71

    NEUTRON NUMBER: 109

    CHARGE: 0

<h2>_____________________________________</h2>

(III)  ATOMIC NUMBER: 40

    MASS NUMBER: 86

    PROTON NUMBER: 40

    ELECTRON NUMBER: 38

    NEUTRON NUMBER: 46

    CHARGE: +2

<h2>_____________________________________</h2>

(IV)  ATOMIC NUMBER: 92

    MASS NUMBER: 238

    PROTON NUMBER: 92

    ELECTRON NUMBER: 86

    NEUTRON NUMBER: 146

    CHARGE: +6

<h2>_____________________________________</h2>

(V) ATOMIC NUMBER: 82

    MASS NUMBER: 206

    PROTON NUMBER: 82

    ELECTRON NUMBER: 78

    NEUTRON NUMBER: 124

    CHARGE: +4

<h2>_____________________________________</h2>

(VI) ATOMIC NUMBER: 34

    MASS NUMBER: 79

    PROTON NUMBER: 34

    ELECTRON NUMBER: 36

    NEUTRON NUMBER: 45

    CHARGE: -2

<h2>_____________________________________</h2>

(VII) ATOMIC NUMBER: 48

    MASS NUMBER: 113

    PROTON NUMBER: 48

    ELECTRON NUMBER: 49

    NEUTRON NUMBER: 65

    CHARGE: -1

<h2>_____________________________________</h2>

(VIII) ATOMIC NUMBER: 21

    MASS NUMBER: 42

    PROTON NUMBER: 21

    ELECTRON NUMBER: 21

    NEUTRON NUMBER: 21

    CHARGE: 0

<h2>_____________________________________</h2>

(IX) ATOMIC NUMBER:

    MASS NUMBER:

    PROTON NUMBER:

    ELECTRON NUMBER:

    NEUTRON NUMBER:

    CHARGE:

<h2>_____________________________________</h2>

(X) ATOMIC NUMBER: 83

    MASS NUMBER: 209

    PROTON NUMBER: 83

    ELECTRON NUMBER: 80

    NEUTRON NUMBER: 126

    CHARGE: +3

<h2>_____________________________________</h2>

(XI) ATOMIC NUMBER: 47

    MASS NUMBER: 108

    PROTON NUMBER: 47

    ELECTRON NUMBER: 47

    NEUTRON NUMBER: 61

    CHARGE: 0

<h2>_____________________________________</h2>

(XII) ATOMIC NUMBER: 49

    MASS NUMBER: 116

    PROTON NUMBER: 49

    ELECTRON NUMBER: 46

    NEUTRON NUMBER: 67

    CHARGE: +3

<h2>_____________________________________</h2>

(XIII) ATOMIC NUMBER: 53

    MASS NUMBER: 128

    PROTON NUMBER: 53

    ELECTRON NUMBER: 54

    NEUTRON NUMBER: 75

    CHARGE: -1

<h2>_____________________________________</h2>

(XIV) ATOMIC NUMBER: 76

    MASS NUMBER: 188

    PROTON NUMBER: 76

    ELECTRON NUMBER: 72

    NEUTRON NUMBER: 112

    CHARGE: +4

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
4 0
3 years ago
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