atomic number of elements are the number of protons
in neutral atoms number of protons are equal to number of electrons
electrons are responsible for the chemical bonding in atoms
bonding depends on the number of valence electrons in the outermost shells.
atom A with 11 protons have 11 electrons, electronic configuration is - 2,8,1
atom B with 17 protons have 17 electrons, electron configuration is - 2,8,7
A has 1 valence electron and B has 7 valence electrons
therefore A prefers to give away its one valence electron and have a complete outer shell and B prefers to take in that one electron from A to become a complete octet.
The type of bond is an ionic bond formed by the transfer of electrons from one species to another species
answer is ionic
<u>Answer:</u> The amount of pure antifreeze that must be added is 6.4 gallons
<u>Explanation:</u>
We are given:
Percent of antifreeze given = 10 %
Amount of solution = 8 gallons
Let the amount of pure antifreeze be 'x'
Calculating the amount of pure antifreeze:
Let the amount of pure antifreeze added in the solution be 'y'
Percent of solution to be made = 50 %
So,
Hence, the amount of pure antifreeze that must be added is 6.4 gallons
Answer:
<h3>The answer is 0.49 mL</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 2.34 g
density = 4.78 g/mL
We have
We have the final answer as
<h3>0.49 mL</h3>
Hope this helps you
Nonmetals which are located in the second row form pi bonds
more easily than the elements situated in the third row and below. Actually there
are no compounds or molecules known that forms covalent bonds to the noble gas
Ne and Ar. Hence the other second row element which is Carbon, is the element that
forms
pi bonds most readily.
Answer:
<span>C</span>
Answer:
Temperature on beans sprouted
Explanation:
- The variable amount is the amount that changes continuously.
- We calculate the sprout of the bean at which temperature it is sprouting rapid, in that case, the temperature acts as a variable amount.
