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3 years ago

A current of 4 amps is running through a circuit with a resistance of 2ohms.What is the voltage.Show working

Physics

1 answer:

Rufina [12.5K]3 years ago

7 0

Voltage = current * resistance
V = I*R
I = 4 A
R = 2 ohm
V = 4 A * 2 ohm
= 8 volt

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3 years ago

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Car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver not

musickatia [10]

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Part A: $t = v_0/a_0$

Part B: $t = v_0/a_0$

Part C: $v_0^2/a_0$

Explanation:

Part A:

We will use the following kinematics equation:

$v = v_0 + at\\0 = v_0 - a_0t\\t = \frac{v_0}{a_0}$

Part B:

We will use the same kinematics equation:

$v = v_0 + at\\v_0 = 0 + a_0t\\t = \frac{v_0}{a_0}$

Part C:

The total time takes is 2t.

So the train moves a distance of

$x = v_0(2t) = 2v_0(\frac{v_0}{a_0}) = \frac{2v_0^2}{a_0}$

And the car moves a distance in Part A and in Part B:

$d_A = v_0t + \frac{1}{2}at^2 = v_0(\frac{v_0}{a_0}) - \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{a_0} - \frac{v_0^2}{2a_0} = \frac{v_0^2}{2a_0}\\d_B = v_0t + \frac{1}{2}at^2 = 0 + \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{2a_0}$

So the total distance that the car traveled is $d = \frac{v_0^2}{a_0}$

The difference between the train and the car is

$x - d = \frac{2v_0^2}{a_0} - \frac{v_0^2}{a_0} = \frac{v_0^2}{a_0}$

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3 years ago

A string of length 0.67 m and mass 2.0 g is held at both ends under tension. The string

ikadub [295]

Answer:

The value is $\lambda = 0.335 \ m$

Explanation:

From the question we are told that

The length of the string is $l = 0.67 \ m$

The mass is $m = 2.0 \ g = 0.002 \ kg$

The frequency produced at fourth harmonic vibration(i.e n =4 ) is $f = 700 \ Hz$

Generally the wavelength of the string is mathematically represented as

$\lambda = \frac{ 2L }{n }$

=> $\lambda = \frac{ 2 * 0.67 }{ 4 }$

=> $\lambda = 0.335 \ m$

7 0

3 years ago