All categories

3 years ago

A package is weighed at 4 kg to the nearest kg.

Mathematics

1 answer:

Shtirlitz [24]3 years ago

4 0

Answer:

3.99kg

Step-by-step explanation:

you can find it by 4kg minus 1 g that stills counts as rounding

You might be interested in

What is 15 divide by 5/9

slavikrds [6]

3/9 is the answer I got

5 0

4 years ago

Read 2 more answers

Tell whether the expressions modeled below are equivalent. Explain how you know.

vovangra [49]

Answer:

they're not

Step-by-step explanation:

when you distribute the 2 into (x-3) you get 2x-6

and thats not equivalent to 2x-3

6 0

3 years ago

Can you solve for y plz

vredina [299]

Solve the top equation for x and then substitute that into the bottom equation and solve for y:
Top equation: subtract 4 from both sides to get x = y - 4
Substitution and simplify:
y = 4(y - 4) - 10
y = 4y - 16 - 10
y = 4y - 26
-3y = -26
y = 26/3 or 8 1/3 or 8.333 (those are all the same but in different forms)

8 0

3 years ago

I need help answering

I am Lyosha [343]

8(1/4) - 1 + 0.5(10)

8/4 - 1 + 5

2 - 1 + 5

1 + 5 = 6

4 0

4 years ago

Read 2 more answers

If all the possible random samples with n = 36 scores are selected from a normal population with µ = 50 and σ = 18, and the mean

ozzi

Answer:

Expected Value of M is 50 and the Standard Error of M is 3

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation, also called standard error $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

µ = 50 and σ = 18

For the sample

Mean 50 and standard error $s = \frac{18}{\sqrt{36}} = 3$ .

The answer is:

Expected Value of M is 50 and the Standard Error of M is 3

7 0

3 years ago