Reasoning Which of these is the best estimate for 150% of 60?

Mathematics

1 answer:

Lunna [17]2 years ago

3 0

Answer:

jugyjhghg

Step-by-step explanation:

qu neo cahg espanol uku hjery

You might be interested in

Which statement is true about judy's method?

aniked [119]

A. Judy made a mistake between Steps 1 and 2
To factor $x^{2} - 16$ , you have to factor it as $(x-2)(x+2)(x-4)$ , not $(x-2)(x+8)$ , because that will leave an extra 6x because of 8x - 2x.

3 0

3 years ago

Read 2 more answers

Is line m: -x+2y=6 parallel, perpendicular, or neither parallel nor perpendicular to line n: y=-2x+6?

Serhud [2]

Make them both equal to y

y=-2x+6

2y=x+6 y=1/2x+3

These are perpendicular since ones slope is -2 and the other is the opposite, 1/2.

7 0

2 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$