Answer:
(a) Along the xy-plane,
7x + 6y = 0
(b) Along the yz-plan,
2y - 3z = 0
(c) Along the xz-plane,
7x - 3z = 0
Step-by-step explanation:
To describe the given set.
Given the plane (7, 6, -3),
We have the equation as
7x + 6y - 3z = 0
(a) Along the xy-plane, z = 0, and we have
7x + 6y = 0
(b) Along the yz-plan, x = 0, and we have
6y - 3z = 0
Or
2y - 3z = 0
(c) Along the xz-plane, y = 0, and we have
7x - 3z = 0
Answer:
Step-by-step explanation:
We have the compound inequality:
Let's solve each of them individually first:
We have:
Divide both sides by 2:
Add 1 to both sides:
We have:
Subtract from both sides:
Divide both sides by -4:
Hence, our solution set is:
Answer:
x^2+8x+16
(x+4)^2
Step-by-step explanation:
x^2 +8x
Take the coefficient of the x term
8
Divide by 2
8/2 =4
Square it
4^2 =16
x^2+8x+16
We can factor it into
(x+8/2) ^2
(x+4)^2
