Answer
given,
largest diameter of balls = 9.52 mm = 0.00476 m
radius = 0.00476
smallest diameter of ball = 2.38 mm = 0.00238 m
radius = 0.00119
viscosity = 1.5 Pa.s
density of the ball = 1.42 g/cm
![F = 6\pi \eta r V_t](https://tex.z-dn.net/?f=F%20%3D%206%5Cpi%20%5Ceta%20r%20V_t)
![F = \dfrac{mv}{t}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7Bmv%7D%7Bt%7D)
![F = \dfrac{\dfrac{4}{3}\pi\ r^3\times (\rho-\sigma) \times 0.99 V_T}{t}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7B%5Cdfrac%7B4%7D%7B3%7D%5Cpi%5C%20r%5E3%5Ctimes%20%28%5Crho-%5Csigma%29%20%5Ctimes%200.99%20V_T%7D%7Bt%7D)
![6\pi \eta r V_t = \dfrac{\dfrac{4}{3}\pi\ r^3\times rho \times 0.99 V_T}{t}](https://tex.z-dn.net/?f=6%5Cpi%20%5Ceta%20r%20V_t%20%3D%20%5Cdfrac%7B%5Cdfrac%7B4%7D%7B3%7D%5Cpi%5C%20r%5E3%5Ctimes%20rho%20%5Ctimes%200.99%20V_T%7D%7Bt%7D)
![t = \dfrac{\dfrac{4}{3}\pi\ r^3\times rho \times 0.99 V_T}{6\pi \eta r V_t}](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7B%5Cdfrac%7B4%7D%7B3%7D%5Cpi%5C%20r%5E3%5Ctimes%20rho%20%5Ctimes%200.99%20V_T%7D%7B6%5Cpi%20%5Ceta%20r%20V_t%7D)
![t= \dfrac{0.22 r^2 (\rho-\sigma) }{\eta}](https://tex.z-dn.net/?f=t%3D%20%5Cdfrac%7B0.22%20r%5E2%20%28%5Crho-%5Csigma%29%20%7D%7B%5Ceta%7D)
for small balls
![t= \dfrac{0.22\times 0.00119^2 (1460-1300)}{1.5}](https://tex.z-dn.net/?f=t%3D%20%5Cdfrac%7B0.22%5Ctimes%200.00119%5E2%20%281460-1300%29%7D%7B1.5%7D)
t = 0.033 ms
for larger ball
![t= \dfrac{0.22\times 0.00476^2 (1460-1300)}{1.5}](https://tex.z-dn.net/?f=t%3D%20%5Cdfrac%7B0.22%5Ctimes%200.00476%5E2%20%281460-1300%29%7D%7B1.5%7D)
t = 0.531 ms
50 g = 0.5 kg. a = 5 / 0.5 = 10 m/s^2.
<span>The next step of the scientific method is to analyze the results and draw conclusions. After that step, if the results agree with the hypothesis, then the results should be communicated. If the results do not support the original hypothesis, then the biologist must go back to the beginning and reformulate their hypothesis based on the results of the experiment.</span>
D. The flow of energy,heat, and work
![\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}](https://tex.z-dn.net/?f=%5Chuge%5Cunderline%7B%5Cunderline%7B%5Cboxed%7B%5Cmathbb%20%7BEXPLANATION%7D%7D%7D%7D)
The heat capacity is given by the expression:
![\longrightarrow \sf{\triangle Q= m \triangle C \triangle T}](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%7B%5Ctriangle%20Q%3D%20m%20%5Ctriangle%20C%20%20%5Ctriangle%20%20%20T%7D)
![\longrightarrow \sf{Q= \: Heat}](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%7BQ%3D%20%5C%3A%20Heat%7D)
![\longrightarrow \sf{M= \: Mass}](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%7BM%3D%20%5C%3A%20Mass%7D)
![\longrightarrow \sf{C= \: Specific \: Heat}](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%7BC%3D%20%5C%3A%20Specific%20%5C%3A%20Heat%7D)
![\longrightarrow \sf{T= \: Temperature}](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%7BT%3D%20%5C%3A%20Temperature%7D)
![\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}](https://tex.z-dn.net/?f=%5Chuge%5Cunderline%7B%5Cunderline%7B%5Cboxed%7B%5Cmathbb%20%7BANSWER%3A%7D%7D%7D%7D)
When the
is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in
, we can then determine the specific heat "C" by simply remplazing in the expression.