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nlexa [21]
3 years ago
12

An aluminum rod is 300m and at 25 degree Celsius. Calculate the change in rod

Physics
1 answer:
Schach [20]3 years ago
6 0

Answer:

Explanation:

540

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What is the correct definition of a fracture?
MA_775_DIABLO [31]

The correct definition of a fracture is break in the bone

<u>Explanation:</u>

When nay injury results in the breaking or causing any cracking in the bones of any parts then this will lead to fracture. When the injury caused is near the ligament or tissue in which the bone is connected or attached then it will lead to an avulsion fractures. Thus this will lead to the pulling of bone form the original position thereby leading more pain in the spot associated with the fracture.

Sports people are the victims of this type of fracture. Fracture may occur anywhere mostly legs,hands,ankle,hip and elbow. sometimes it may be in finger, shoulder,knee,etc. The main symptoms that are associated with fracture includes, selling, inability in moving the fractured part or pain associated when trying to move that part, Loss of the affected part's function,etc.

4 0
3 years ago
Due today HELP HELP HELP
Anna [14]

Vas happenin!

Independent variable : amount of water each day

Dependent variable: water on the windsill

Hypotheses: Ben wants to try by adding water each day to two different places. Will that work? Will that effect the water?


Hope this helps you out

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-Zayn Malik
5 0
2 years ago
A car drives around a curve with radius 539 m at a speed of 32.0 m/s. The road is banked at 5.00°. The mass of the car is 1.40 ×
HACTEHA [7]

Answer:

f_r = 150.47 N

Explanation:

given,

r = 539 m

v = 32 m/s

road banked at = 5°

∑ F_x

\dfrac{mv^2}{r}= N sin \theta + f_r cos \theta

∑ F_y = 0

0 = N cos \theta - f_r sin \theta - mg

N = \dfrac{f_rsin \theta + mg}{cos \theta}

\dfrac{mv^2}{r}= (\dfrac{f_rsin \theta + mg}{cos \theta})sin \theta + f_r cos \theta

              = f_r sin \theta tan \theta + mg tan \theta + f_r cos \theta

        f_r = \dfrac{\dfrac{mv^2}{r}- mg tan\theta}{sin\theta tan \theta + cos \theta}

         f_r = \dfrac{\dfrac{1.4\times 10^3 \times 32^2}{539}- 1.4\times 10^{3}\times 9.8 \times 0.087}{0.087 \times 0.087 + 0.996}

f_r = 150.47 N

8 0
3 years ago
4<br> Explica las características principales de las fuer-<br> zas de acción y reacción.
Naya [18.7K]
-Surgen de una interacción.
-Nunca aparece una sola: son dos y simultáneas.
-Actúan sobre cuerpos diferentes: una en cada cuerpo.
-Nunca forman un par de fuerzas: tienen la misma línea de acción.
-Un cuerpo que experimenta una única interacción no está en equilibrio, pues sobre el aparece una fuerza unica que lo acelera. Para estar en equilibrio se requieren por lo menos dos interacciones.




Las mas importantes son la 2,3,4 característica
5 0
3 years ago
If an object travels at a constant speed in a circular path, the acceleration of the object is:
Vilka [71]

Answer:

1- The acceleration of the object is larger in magnitude the smaller the radius of the circle.

Explanation:

The acceleration of an object in a circular path is

a = \frac{v^2}{r}

As can be seen from the equation, if the radius of the circle is decreases, the magnitude of the acceleration increases.

As for the direction of the acceleration, it is always towards the center, and it is always perpendicular to the direction of the velocity.

6 0
3 years ago
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