An aluminum rod is 300m and at 25 degree Celsius. Calculate the change in rod

A body has a mass of 2kg.it accelerats from 20m/s to 40m/s in 4 seconds.the resultant force is<br>

GaryK [48]

The resultant force is 8N

Given that mass is 2kg , v= 40m/s, u =20m/s and we need to calculate resultant force
F=ma

m is given
so for a
v-u/t=a { first equation of motion }

40-20/4= 4
so a=4

F = ma =2*4 = 8N
The difference between the forces that are acting on an object as part of a system is known as the resultant force.
v = u + at is the first equation of motion. Here, v denotes the end speed, u the starting speed, an acceleration, and t the passage of time. The first equation of motion is provided by the velocity-time relation, which may be used to calculate acceleration.

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8 0

2 years ago

bonnie pulls a cart that weighs 195 N with a force of 18.0 N. According to Newton's 3rd law, with what force does the cart pull

motikmotik

Answer:

The force exerted by the cart on Bonnie is - 18.0 N

Explanation:

Given;

weight of the cart, w = 195 N

Bonnie's applied force on the cart, F = 18.0 N

According to Newton's 3rd law, action and reaction are equal and opposite.

Thus, the cart will pull back at Bonnie with force of equal magnitude but in opposite direction.

The force exerted by the cart on Bonnie = - 18.0 N

4 0

3 years ago

A tank is 10 m long, 8 m wide, 4 m high, and contains kerosene with density 820 kg/m3 to a depth of 3.5 m. (Use 9.8 m/s2 for the

Alexxandr [17]

Answer:

28,126pascal

Explanation:

Hydrostatic pressure exerted on the bottom of the tank can be calculated using the formula

P = hpg where;

h is the depth of the tank = 3.5m

p is the density of the kerosene = 820kg/m³

g is the acceleration due to gravity = 9.8m/s²

Substituting the values into the formula we have;

P = 3.5×820×9.8

P = 28,126Pascal

5 0

4 years ago

Why did Isaac Newton come up with the three laws of motion

son4ous [18]

He turned his observations into laws, to establish constants and explanations of future scientists.

3 0

4 years ago

A ship sailing in the Gulf Stream is heading 25.0º west of north at a speed of 4.00 m/s relative to the water. Its velocity rela

ASHA 777 [7]

Answer:

Velocity of Gulf Stream= $34.5^\circ$ west of north at a speed of $2.03\ \rm m/s$

Explanation:

Given

speed of ship relative to Gulf stream= $25^\circ$ west of north at a speed of 4 m/s

speed of ship relative to earth= $5^\circ$ west of north at a speed of 4 .8 m/s

Let $V_S$ be the velocity of the ship relative to the earth and $V_{sg}$ be the velocity of the ship with respect to the Gulf stream

Let the west direction be negative x axis and north direction be positive x axis

Now

$V_{sg}=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\V_s-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\-4.8\sin5^\circ \vec i+4.8\cos5^\circ \vec j-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\Vg=-1.68\vec\ i+1.156\vec\ j\ \rm m/s\\$

magnitude of the velocity is given by

$V_g=\sqrt{(1.68^2+1.156^2)}\\V_g=2.03\ \rm m/s\\$

Let the velocity of gulf stream makes an angle $\theta$ with the positive y axis we have

$\tan\theta=\dfrac{1.156}{1.68}\\\theta=34.5^\circ$

Velocity of Gulf Stream $34.5^\circ$ west of north at a speed of $2.03\ \rm m/s$

8 0

3 years ago