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Masja [62]
3 years ago
11

It is generally a good idea to gain an understanding of the "size" of units. Consider the objects listed and calculate the magni

tude of their momentum in SI units. A ladybug weighing 31.80 mg flies by your head at 2.53 mi/h.
Physics
1 answer:
Alex3 years ago
5 0

Answer:

Explanation:

The standard unit of momentum Is kgm/s

And momentum is the product of mass and velocity

Then,

Momentum = mass × velocity

P = mv

Where

m is mass in kg

v is velocity in m/s

Now,

Given that,

M = 31.8mg

1mg = 10^-3g

So, m = 31.8 × 10^-3g

Also, 1000g = 1kg → 1g = 10^-3 kg

So,

m = 31.8 × 10^-3 × 10^-3kg

m = 31.8 × 10^-6 kg

v = 2.53mi/hr

1mile = 1609.34 m

1 hour = 3600seconds

Then,

v = 2.53 × 1609.34m/ 3600s

v = 1.13 m/s

So, momentum is given as

P = mv

P = 31.8 × 10^-6 × 1.13

P = 3.597 × 10^-5 kgm/s

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If it takes 20n to move a box, how much power will be needed to move the box a diatance
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The power applied to move the box anywhere is

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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

brainly.com/question/7956557

#LearnwithBrainly

3 0
3 years ago
50 points Answer fast please
erma4kov [3.2K]

Answer:

22 hours

Explanation:

6 0
3 years ago
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