Ask question

Ask question

All categories

3 years ago

11

It is generally a good idea to gain an understanding of the "size" of units. Consider the objects listed and calculate the magni

tude of their momentum in SI units. A ladybug weighing 31.80 mg flies by your head at 2.53 mi/h.

1 answer:

Alex3 years ago

5 0

Answer:

Explanation:

The standard unit of momentum Is kgm/s

And momentum is the product of mass and velocity

Then,

Momentum = mass × velocity

P = mv

Where

m is mass in kg

v is velocity in m/s

Now,

Given that,

M = 31.8mg

1mg = 10^-3g

So, m = 31.8 × 10^-3g

Also, 1000g = 1kg → 1g = 10^-3 kg

So,

m = 31.8 × 10^-3 × 10^-3kg

m = 31.8 × 10^-6 kg

v = 2.53mi/hr

1mile = 1609.34 m

1 hour = 3600seconds

Then,

v = 2.53 × 1609.34m/ 3600s

v = 1.13 m/s

So, momentum is given as

P = mv

P = 31.8 × 10^-6 × 1.13

P = 3.597 × 10^-5 kgm/s

You might be interested in

The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an

Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

$\Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t$

or, $\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

Putting the given values into the above formula as follows.

$\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

= $\frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}$

= 0.326 $rad/s^{2}$

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 $rad/s^{2}$ .

5 0

3 years ago

Four uniform spheres, with masses mA = 200 kg, mB = 250 kg, mC = 1700 kg, and mD = 100 kg, have (x, y) coordinates of (0, 50 cm)

rusak2 [61]

Answer:

$F_2=2.43\times10^{-19}\ N$

$\theta=21.496^{\circ}$ in the anticlockwise direction from the positive x- axis.

Explanation:

Given are the masses of various spheres with their names in subscript:

$m_A=200\ kg$

$m_B=250\ kg$

$m_C=1700\ kg$

$m_D=100\ kg$

Now their respective coordinate positions (in cm) are as given below:

$P_A=(0,50)$

$P_B=(0,0)$

$P_C=(-80,0)$

$P_D=(40,0)$

<u>Now force on B due to A:</u>

$F_{BA}=G\times \frac{200\times 250}{50^2}$

$F_{BA}=20G\ N$

<u>Now force on B due to C:</u>

$F_{BC}=G\times \frac{1700\times 250}{80^2}$

$F_{BC}=66.406G\ N$

<u>Now force on B due to D:</u>

$F_{BD}=G\times \frac{100\times 250}{40^2}$

$F_{BD}=15.625G\ N$

<em>We observe that the forces due to masses C&D act opposite in direction.</em>

<u>So, the net force in the x-direction:</u>

$F_x=F_{BC}-F_{BD}$

$F_x=66.406G-15.625G$

$F_x=50.781G\ N$ in the positive x-direction

<em>We have only one force in y-direction due to mass A.</em>

So,

$F_y=20G\ N$ in the positive y-direction.

<u>Now the net force:</u>

$F_2=\sqrt{F_y^2+F_x^2}$

$F_2=\sqrt{(20G)^2+(50.781G)^2}$

$F_2=54.5776G^2\ N$

$F_2=2.43\times10^{-19}\ N$

<u>Now the direction of this force with respect to x-axis:</u>

$tan\ \theta=\frac{F_y}{F_x}$

$tan\ \theta=\frac{20G}{50.781G}$

$\theta=21.496^{\circ}$ in the anticlockwise direction from the positive x- axis.

3 0

3 years ago

Read 2 more answers

Which is a sign of a chemical change?

Molodets [167]

Answer: When chemical change occurs you will see like, the change of color or bubbles will form, the temperature will change, and maybe the odor too.

5 0

3 years ago

Read 2 more answers

Karen runs sets in basketball practice. She starts from a line runs 2.0 m, returns to the line, runs 4.0 m, to the line, runs 6.

Aleonysh [2.5K]

D. distance = 23 m, displacement = + 1 m

Explanation:

Let's remind the difference between distance and displacement:

- distance is a scalar, and is the total length covered by an object, counting all the movements in any direction

- displacement is a vector connecting the starting point and the final point of a motion, so its magnitude is given by the length of this vector, and its direction is given by the direction of this vector.

In this case, the distance covered by Karen is given by the sum of all its movements:

$distance = 2.0 m + 2.0 m+4.0 m+4.0 m +6.0 + 5.0 m=23.0 m$

The displacement instead is given by the difference between the final point (1.0 m in front of the starting line) and the starting point (the starting line, 0 m):

$displacement = +1.0 m-0 m=+1 m$

8 0

3 years ago

Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each ot

jolli1 [7]

Answer:

The electric force between them if the pieces of grain are 2 cm apart is $3.15\times 10^{-11}\textrm{ N}$ .

Explanation:

Given:

Charge on one grain, $Q_{1}=6\times 10^{-10}\textrm{ C}$

Charge on another grain, $Q_{2}=2.3\times 10^{-15}\textrm{ C}$

Separation between them, $d=2\textrm{ cm}=0.02\textrm{ m}$

Electric force acting between two charges $Q_{1}\textrm{ and }Q_{2}$ separated by a distance $d$ is given as:

$F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}$

Where, $k$ is Coulomb's constant equal to $9\times 10^9\textrm{ }Nm^2/C^2$ .

Now, plug in all the values and solve for $F{elec}$ .

$F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}$

Therefore, the electric force between them if the pieces of grain are 2 cm apart is $3.15\times 10^{-11}\textrm{ N}$ .

3 0

3 years ago