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anastassius [24]
2 years ago
7

What is 6 divided by 46.8

Mathematics
2 answers:
sashaice [31]2 years ago
8 0
The rounded answer of this question is 0.128 or 0.13
Andrew [12]2 years ago
7 0
6 divided by 46.8 would be .1282
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Find the simple interest. <br><br> p = $12,000; r = 9%; t = 4 yr.<br> $
aleksklad [387]
SI=prt/100

P=12,000
R=9%
T=4


SI= prt/100
=12,000*9*4/100
=432,000/100
=4,320
3 0
3 years ago
Write each set in the indicated form.
viktelen [127]

Answer:

a) The set of natural numbers greater than or equal to 3 and less than or equal to 6.

b) {3,4,5,6}

Step-by-step explanation:

a) The Roster form is given as {6,8,10,12,...}

The descriptive form is a phrase that describes the given set.

The descriptive form is: <em>The set of even natural numbers greater than or equal to 6.</em>

b) The descriptive form is : The set of natural numbers greater than or equal to 3 and less than or equal to 6.

The Roster form is obtained by listing the numbers between 3 and 6 inclusive in curly brackets.

The Roster form is : {3,4,5,6}

3 0
3 years ago
A bank requires a borrower to pay 1 ½ points for a loan. Find the amount of the loan origination fee for a loan of $89,000.
mezya [45]
0.015×89,000
=1,335
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5 0
3 years ago
Find the equation of the line through point (−5,5) and perpendicular to y=59x−4
VARVARA [1.3K]

Answer:

Step-by-step explanation:

5 0
1 year ago
Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) 5, 1,
Dahasolnce [82]

Answer:

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

Step-by-step explanation:

For a given vector a = ai + aj + ak, its direction cosines are the cosines of the angles which it makes with the x, y and z axes.

If a makes angles α, β, and γ (which are the direction angles) with the x, y and z axes respectively, then its direction cosines are: cos α, cos β and cos γ in the x, y and z axes respectively.

Where;

cos α = \frac{a . i}{|a| . |i|}               ---------------------(i)

cos β = \frac{a.j}{|a||j|}               ---------------------(ii)

cos γ = \frac{a.k}{|a|.|k|}             ----------------------(iii)

<em>And from these we can get the direction angles as follows;</em>

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

Now to the question:

Let the given vector be

a = 5i + j + 4k

a . i =  (5i + j + 4k) . (i)

a . i = 5         [a.i <em>is just the x component of the vector</em>]

a . j = 1            [<em>the y component of the vector</em>]

a . k = 4          [<em>the z component of the vector</em>]

<em>Also</em>

|a|. |i| = |a|. |j| = |a|. |k| = |a|           [since |i| = |j| = |k| = 1]

|a| = \sqrt{5^2 + 1^2 + 4^2}

|a| = \sqrt{25 + 1 + 16}

|a| = \sqrt{42}

Now substitute these values into equations (i) - (iii) to get the direction cosines. i.e

cos α = \frac{5}{\sqrt{42} }

cos β =  \frac{1}{\sqrt{42} }              

cos γ =  \frac{4}{\sqrt{42} }

From the value, now find the direction angles as follows;

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

α =  cos⁻¹ ( \frac{5}{\sqrt{42} } )

α =  cos⁻¹ (\frac{5}{6.481} )

α =  cos⁻¹ (0.7715)

α = 39.51

α = 40°

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

β = cos⁻¹ ( \frac{1}{\sqrt{42} } )

β = cos⁻¹ ( \frac{1}{6.481 } )

β = cos⁻¹ ( 0.1543 )

β = 81.12

β = 81°

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

γ = cos⁻¹ (\frac{4}{\sqrt{42} })

γ = cos⁻¹ (\frac{4}{6.481})

γ = cos⁻¹ (0.6172)

γ = 51.89

γ = 52°

<u>Conclusion:</u>

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

3 0
3 years ago
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