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melamori03 [73]
2 years ago
7

What is the value of x in the figure? Enter your answer in the box. 145° (2x + 15)° x=

Mathematics
2 answers:
Nikolay [14]2 years ago
8 0

Answer:

Answer: x=65

Step-by-step explanation:

Since they're vertical angles both sides are equal to 145 degrees

So, 145-15= 130 to get rid of the constant

Then, 130/2=65

To check you work add up all of your solutions to get 145

2*65=130 & 130+15=145

Therefore, x=65

SSSSS [86.1K]2 years ago
5 0
Hi I’m sure about x=65
Hope it helps
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Please help and i have to be done with my work by tomorrow
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<span>let length of painting = L
 and width = W
from area = length times width
180 inch^2 = L  times W
but L = 5/4  times W
180 inch^2 = 5/4 times W times W

W^2 = (4 x 180)/5
W = 12
but L = 5/4 x W
L = 5/4 x 12
L = 15
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<span>Answer: The dimensions of the painting are </span><u>12 x 15 inches</u>.
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3 years ago
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Dafna1 [17]
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3 years ago
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If (a,-3) is a point in the graph of y=x^2+4 what is a?
netineya [11]

Answer:

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3 years ago
IF CD=AD, and CB=AD. Then 1=2
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You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, \bar x = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0
3 years ago
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