Complete question :
Suppose someone gives you 8 to 2 odds that you cannot roll two even numbers with the roll of two fair dice. This means you win $8 if you succeed and you lose $2 if you fail. What is the expected value of this game to you? What can you expect if you play 100 times.
Answer:
$0.5 ; win $50 with 100 rolls
Step-by-step explanation:
From a roll of two fair dice; probability of obtaining an even number :
Even numbers = (2, 4, 6) = 3
P = 3 /6 = 1 /2
For 2 fair dice ; probability of rolling two even numbers : independent event.
1/2 * 1/2 = 1/4
Hence, p(success) = 1/4 ; P(failure) = 1 - 1/4 = 3/4
Probability table
Winning = $8 or loss = - $2
X : ____ 8 ______ - 2
P(x) __ 1/4 ______ 3/4
Expected value : E(x) = ΣX*P(x)
E(x) = (8 * 1/4) + (-2 * 3/4)
E(x) = 2 - 1.5
E(x) = $0.5
Since expected value is positive, the expect to win
If played 100 times;
Expected value = 100 * $0.5 = $50
To find the solution to this problem, you would do the opposite of division which is multiplication.
Use the terms you have to plug into your new equation;
0.6 x 1.4 = .84
To check your work you would plug in .84 where the '?' is;
.84/.6= 1.4
There you have the original equation you began with.
Therefore, .84 would be your final answer.
Answer:
x = 10
Step-by-step explanation:
Hello!
Answer:
1. 
*The answer must have A NEGATIVE SIGN ONLY!*
2. 
*The answer must have A POSITIVE SIGN ONLY!*
3. 
*The answer must have a NEGATIVE SIGN ONLY!*
Step-by-step explanation:
1. 9w=-54
First, you divide by 9 both sides of an equation.
9w/9=-54/9
Simplify.
-54/9=-6
<u><em>W=-6 is the final answer.</em></u>
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2. b-12=3
First you add by 12 both sides of an equation.
b-12+12=3+12
Add by the numbers from left/right.
3+12=15
<u><em>b=15 is the final answer.</em></u>
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3. n/4=-11
First you multiply by 4 both sides of an equation.
4n/4=4(-11)
Multiply by the numbers from left/right.
4*-11=-44
<u><em>n=-44 is the final answer.</em></u>
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Hope this helps you!
Have a great day! :)
:D
-Charlie
Thanks!
