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spin [16.1K]
4 years ago
7

A test consists of 10 multiple choice questions, each with five possible answers, one of which is correct. To pass the test a st

udent must get 60% or better on the test. If a student randomly guesses, what is the probability that the student will pass the test?
Mathematics
1 answer:
Softa [21]4 years ago
8 0

Answer:

0.006369

Step-by-step explanation:

Given that a test consists of 10 multiple choice questions, each with five possible answers, one of which is correct.

By mere guessing p = probability for a right answer = 1/5 =0.20

There are two outcomes and each question is independent of the other.

X no of questions right is Bin (10,0.20)

the probability that the student will pass the test

= prob of getting more than 60%

=P(X\geq 6)

=0.006369

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Which number is rational?
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3 years ago
Helene is finding the sum (9 10i) (–8 11i). She rewrites the sum as (–8 11)i (9 10)i. Which statement explains the property of a
Andreyy89

She made the mistake of grouping unlike terms and factorizing.

Given that

Helene is finding the sum (9 + 10i) + (–8 + 11i).

She rewrites the sum as (–8 + 11)i + (9 + 10)i.

We have to determine

Which statement explains the property of addition that she made an error in using?

According to the question

The mistake she did is in the second term distributing.

(9+10i) is not equal to (9+10)i

Similarly (-8+11i) is not equal to (-8+11)i.

The correct method she should have done is given below;

Grouping real terms together and imaginary terms together and finding the sum is,

\rm =  (9 + 10i) + (-8 + 11i)\\\\= 9+10i-8+11i\\\\= (9-8) +(10i+11i)\\\\=1+21i

Hence, she made the mistake of grouping unlike terms and factorizing.

To know more about Complex Number click the link given below.

brainly.com/question/10078818

6 0
3 years ago
Kara did a survey to determine to study the types of pets that students in her school had. She surveyed 300 students and found t
julsineya [31]

Answer:

(C)81

Step-by-step explanation:

Total Number of Students =300

Percentage who had cats, n(C) = 40%

Percentage who had both cats and dogs , n(C \cap D) = 12%

Percentage who had neither cats nor dogs, n(C \cup D)' =45%

Now:

Universal Set, U = n(C)+n(D)-n(C \cap D)+n(C \cup D)'

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Therefore:

Number of Students who had dogs

=27% of 300

=81

3 0
3 years ago
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