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3 years ago

15

The beans you ate last night are digested and an odiferous, flammable gas produced the next day. Chemical change or physical cha

nge?

1 answer:

Arturiano [62]3 years ago

7 0

Answer:

Chemical change

Explanation:

The beans you ate turned into a flammable gas some weird thing must have happened in your stomach to make it into gas

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Veseljchak [2.6K]

Answer:

D, when there is a large antelope population

Explanation:

I took the k12 test and got it right

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2 years ago

How would you describe the image formed by a convex mirror? a. upright and larger than object c. inverted and larger than object

Alecsey [184]

One way that I would really describe these kind of mirrors would be like first, these kind of mirrors are for sure <span>virtual, upright, smaller. And this would be only due mainly because this the kind of mirror this would be. So based from my information. So based from your options, the answer would most likely be one of the options that would practically fit this. This would be known to be "</span><span> upright and smaller than object".</span>

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3 years ago

Read 2 more answers

A temperature regime that experiences consistent high temperatures with little seasonality is the?

cupoosta [38]

A temperature regime that experiences consistent high temperatures with little seasonality is the <u>equatorial</u>.

<h3>What is temperature regime?</h3>

These systems have a significant impact on how soils are used and managed, especially when choosing plants that are adapted to the environment. There are 10 different soil temperature regimes: cryic, frigid, hyperthermic, isofrigid, isohyperthermic, isomesic, isothermic, mesic, pergelic, and thermic.

<h3>What is a mesic temperature regime?</h3>

Mesic. At a depth of 50 cm from the soil surface or at a dense, lithic, or paralytic contact, whichever is shallower, the difference between the mean summer and mean winter soil temperatures is greater than 6° C and the mean annual soil temperature is 8° C or higher but lower than 15° C.

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7 0

2 years ago

Carbordum is silicon carbide SiC a very hard material used as an abrasive on sand paper and in other applications. it is prepare

AleksandrR [38]

Answer:

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

Explanation:

The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:

$SiO_2+3C\rightarrow SiC+2CO$

1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.

Mass of SiC = 3.00kg = 3000.00 g

1 kg = 1000 g

Molecular mass of SiC = 40 g/mol

Moles of SiC = $\frac{3000.00 g}{40 g/mol}= 75 mol$

According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.

Then 75 moles of SiC will be produce from:

$\frac{1}{1}\times 75 mol=75 mol$ of silicon dioxide.

mass of 75 moles of silicon dioxde:

$75 mol\times 60 g/mol=4500 g=4.5 kg$

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

3 0

4 years ago

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10

masya89 [10]

<u>Answer:</u> The molar mass of unknown gas is 367.12 g/mol

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

$\text{Rate}=\frac{V}{t}$

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So,

$\left(\frac{\frac{V_{X}}{t_{X}}}{\frac{V_{O_2}}{t_{O_2}}}\right)=\sqrt{\frac{M_{O_2}}{M_{X}}}$

We are given:

Volume of unknown gas (X) = 1.0 L

Volume of oxygen gas = 1.0 L

Time taken by unknown gas (X) = 105 seconds

Time taken by oxygen gas = 31 seconds

Molar mass of oxygen gas = 32 g/mol

Molar mass of unknown gas (X) = ? g/mol

Putting values in above equation, we get:

$\left(\frac{\frac{1.0}{105}}{\frac{1.0}{31}}\right)=\sqrt{\frac{32}{M_X}}\\\\M_X=367.12g/mol$

Hence, the molar mass of unknown gas is 367.12 g/mol

3 0

4 years ago