On average suzanne’s street uses 88.75 gallons while jason’s uses 85.9 so suzanne’s street uses more water on a daily average
Yes or course. PEMDAS
Parenthesis
Exponents
Multiplication-Division (solve left to right)
Addition- Subtraction (solve left to right)
example, lets take a simple equation.
32+6x7-1+4²
Let's solve it left to right
You're answer would be 281
But when using PEMDAS your answer is- 89
Check out this video for extra help.
https://www.khanacademy.org/math/pre-algebra/pre-algebra-arith-prop/pre-algebra-order-of-operations/...
The equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)
<h3>What is the equation of the ellipse represented in the graph?</h3>
Herein we have a representation of an ellipse in the image attached aside, ellipses are characterized by the following <em>standard</em> formula:
(x - h)² / a² + (y - k)² / b² = 1 (1)
Where:
- (h, k) - Coordinates of the center
- a, b - Lengths of the semiaxes
Please notice that ellipse will be vertical if b > a, otherwise it will be horizontal. The graph exhibits a <em>vertical</em> ellipse centered at the origin and therefore we conclude that (h, k) = (0, 0) and b > a (b = 10, a = 2). Finally, the equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)
To learn more on ellipses: brainly.com/question/14281133
#SPJ1
Answer: a) 2:1. b) 3. c) Perimeter of ΔEFG=36 Perimeter of ΔHIJ=18. d) 2:1
Step-by-step explanation:
a) Find the ratio of GF and JI. 16:8. Simplify by dividing both by 8 to get 2:1.
b) Set up this equation: 6/16=x/8. Cross-multiply. 6*8=48. Divide by 16. 48/16=3.
c) First find the length of one half of GF by dividing 16 by 2. 16/2=8. Set up the Pythagorean theorem. 8^2+6^2=c^2. Square 8 and 6. 64+36=c^2. Add 64 and 36. 100=c^2. Find the square root of 100. c=10.
EF and EG both measure 10 since they are shown to be congruent. 10+10+16=36.
Next find the length of one half of JI by dividing 8 by 2. 8/2=4. Set up the Pythagorean theorem. Since we know x=3, it will be 4^2+3^2=c^2. Square both 4 and 3. 16+9=c^2. Add 16 and 9. 25=c^2. Find the square root of 25. c=5.
HJ and HI both measure 5 since they are congruent. 5+5+8=18.
d) Find the ratio of the perimeters of ΔEFG and ΔHIJ. 36:18. Simplify by dividing both by 6 to get 6:3. Simplify further by dividing both by 3 to get 2:1.
Answer:
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Step-by-step explanation:
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