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2 years ago

Which graph is a function of x

Mathematics

1 answer:

timurjin [86]2 years ago

5 0

Answer:

the answer is the 2nd one the one with the v shape

Step-by-step explanation:

if you do the vertical line test which is just drawing a vertical line through the line and it intersect the line twice than it is NOT functional

(i think i do not know D:)

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the total cost of 4 pens at rs 20 each,5 pencils at Rs 5 each and 2 boxes at rs 60 each.make equation and solve (INTEGERS) plsss

Julli [10]

Answer:

225 rs

Step-by-step explanation:

cost of 1 pen = 20 rs

total cost of 4 pens = 20×4= 80 rs

cost of 1 pencil = 5 rs

total cost of 5 pencils = 5×5 = 25 rs

cost of 1 box = 60 rs

total cost of 2 boxes = 60×2 = 120 rs

Total= 80+25+120 = 225 rs

4 0

2 years ago

Solve for x ln(3x+2)=4

Rasek [7]

Answer:

x = (e^4 -2)/3

x≈17.533

Step-by-step explanation:

ln(3x+2)=4

raise each side to e

e^ ln(3x+2) = e^4

3x+2 = e^4

subtract 2 from each side

3x = e^4 -2

divide by 3

x = (e^4 -2)/3

putting this in a calculator

x≈17.533

5 0

2 years ago

Read 2 more answers

What is 32% of 150<br><br> Please show work or explain your thinking

artcher [175]

32% of 150 is 48
hope this helps

7 0

2 years ago

A line with a slope of -1/2 passes thru the point (-4,3)...Which equation represents this line?

BaLLatris [955]

Here you go!! Hope this helps!!!!

7 0

2 years ago

Read 2 more answers

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$