1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna11 [10]
3 years ago
5

A car with mass m travels over a hill with a radius of curvature of r at a speed of 15 m/s. What is the normal force on the car

when the car is at the top of the hill?
Physics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

zero

Explanation:

The computation of the normal force is shown below:

As we know that

F_c = mg - N

F_c = mv^2 ÷ r

N = mg - mv^2 ÷ r

N = m(g - v^2 ÷ r)

Assume that

The mass of the car is 1200 kg

And, r = 10 m

So,

= 1200 (9.8 - 15^2 ÷ 10)

= -15240 N

Since it comes in negative so the normal force would be zero

You might be interested in
Infer which group you would expect to contain element 117. Use the periodic table to help you answer this question.
Gre4nikov [31]

Answer:

halogen group

Explanation:

6 0
2 years ago
Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of
Aleonysh [2.5K]

Answer:

r = 0.0548 m

Explanation:

Given that,

Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of 1.90 T directed perpendicular to their velocities.

We need to find the radius of their circular path. The formula for the radius of path is given by :

r=\dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}

m is mass of Singly charged uranium-238 ion, m=3.95\times 10^{-25}\ kg

q is charge

So,

r=\dfrac{1}{1.9}\times \sqrt{\dfrac{2\times 3.95\times 10^{-25}\times 2.2\times 10^3}{1.6\times 10^{-19}}}\\\\r=0.0548\ m

So, the radius of their circular path is equal to 0.0548 m.

4 0
3 years ago
What is one behavior that a plant has that a human would be suprised by
statuscvo [17]
Growing and being able to pollen

3 0
3 years ago
What is the speed of a walking person in m/s if the person travels 1000 m in 1200 seconds?​
Brilliant_brown [7]

Answer:

0.83

Explanation:

to figure out what m/s is you would divide the distance by time.

1000 divided by 1200 is equal to .83  so

.83 m/s as your final answer

4 0
3 years ago
Contrast speed and velocity
Zielflug [23.3K]

Answer:

"Speed" is the rate at which distance is being covered .... the ratio

of distance covered to the time it takes.

"Velocity" is the rate at which distance is being covered .... the ratio

of distance covered to the time it takes ... AND the direction in which

it is covered.  'Speed' with the direction of the motion.

Explanation:

6 0
3 years ago
Other questions:
  • Suppose you go outside and look at three stars. Star A is blue, star B is white, and star C is red. Which star is the hottest, a
    5·2 answers
  • Which word is not a good way to describe exercise?
    11·1 answer
  • A stack of books rests on a level frictionless surface. A force F acts on the stack, and it accelerates at 3.0 m/s2. A 1.0 kg bo
    14·1 answer
  • Matter and energy cycle around our ecosystem, are never being created or destroyed.
    6·2 answers
  • A person's _____________ will change if they move from the Earth to the moon.
    15·1 answer
  • A student sees a newspaper ad for an apartment that has 1330 square feet (ft^2) or floor space. How many square meters of area a
    6·1 answer
  • Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by
    10·1 answer
  • How is property belonging to individuals protected under the Fifth Amendment?
    7·2 answers
  • Why should I care about children in Haiti that are being targeted by Haitian gangs?
    10·1 answer
  • a scooter has a mass of 25 kg. a constant force is exerted on it for 5 s during the time the force is exerted the scooter increa
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!