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Temka [501]
3 years ago
10

Question 26 Unsaved

Physics
1 answer:
vlabodo [156]3 years ago
7 0
The density increases
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Which of these would have particles with the highest kinetic energy? Ice Water Water Vapor
umka2103 [35]
<h2>Answer:</h2>

The correct answer is water vapor.

<h3>Explanation:</h3>
  • In evaporation of water, particles with high kinetic energy tend to leave the water surface.
  • Because high kinetic energy molecules move faster than others breaking bonds with other molecules.
  • And escape the water to air in form of vapors.
  • While the ice water contain molecules with low kinetic energy.

7 0
3 years ago
Read 2 more answers
How temperature, surface tension and the diameter of the tube affect capillary action.​
Alexus [3.1K]

The surface tension acts to hold the surface intact. Capillary action occurs when the adhesion to the surface material is stronger than the cohesive forces between the water molecules. ... Water wants to stick to the glass and surface tension will push the water up, until the force of gravity prevents further rise.

Narrower tube openings allow capillary action to pull water higher

5 0
3 years ago
A ball is thrown straight up at 20 m. What is the balls velocity as it hits the ground?
deff fn [24]

Answer:

<em>The velocity of the ball as it hit the ground = 19.799 m/s</em>

Explanation:

Velocity: Velocity of a body can be defined as the rate of change of displacement of the body. The S.I unit of velocity is m/s. velocity is expressed in one of newtons equation of motion, and is given below.

v² = u² + 2gs.......................... Equation 1

Where v = the final velocity of the ball, g = acceleration due to gravity, s = the height of the ball

<em>Given: s = 20 m, u = 0 m/s</em>

<em>Constant: g = 9.8 m/s²</em>

<em>Substituting these values into equation 1,</em>

<em>v² = 0 + 2×9.8×20</em>

<em>v² = 392</em>

<em>v = √392</em>

<em>v = 19.799 m/s.</em>

<em>Therefore the velocity of the ball as it hit the ground = 19.799 m/s</em>

5 0
3 years ago
A 1 kg ball and a 10 kg ball are dropped from a height of 10 m at the same time. In the absence of air resistance,
RideAnS [48]

Answer:

the two balls will hit the ground at the same time.

Explanation:

The time of dropping, in the following equation, is related to both the distance travel s and the gravitational acceleration g, which are the same for both ball (if we neglect air resistance), no matter what their mass are.

s = gt^2/2

t^2 = 2s/g

So the time it takes to drop 2 balls are the same. They will hit the ground at the same time.

3 0
3 years ago
Between which two points did they travel fastest?
marusya05 [52]

Answer:

During the section CD , the speed is fastest.

Explanation:

The rate of change of distance is called speed.

Speed = distance / time

Its SI unit ism/s. It is a scalar quantity.

The slope of the distance time graph is given by the speed of the object.

Here, the speed of AB is 30/3= 10 m/s .

The speed of BC is = 0 m/s

The speed of CD is (50 - 30)/(6 - 5) = 20 m/s

So, the speed is maximum during the section CD.

7 0
3 years ago
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