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IceJOKER [234]
4 years ago
6

A rocket in deep space has an empty mass of 220 kg and exhausts the hot gases of burned fuel at 2500 m/s. What mass of fuel is n

eeded to reach a top speed of 4000 m/s
Physics
1 answer:
Scilla [17]4 years ago
8 0

Answer:

Explanation:

Let fuel is released at the rate of dm / dt where m is mass of the fuel

thrust created on rocket

= d ( mv ) / dt

= v dm / dt

this is equal to force created on the rocket

= 220 dv / dt

so applying newton's law

v dm / dt = 220 dv / dt

v dm = 220 dv

dv / v = dm / 220

integrating on both sides

∫ dv / v    = ∫ dm / 220

lnv =  ( m₂ - m₁ ) / 220

ln4000 - ln 2500 = ( m₂ - m₁ ) / 220

( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )

( m₂ - m₁ ) = 220 x ( 8.29  - 7.82 )

= 103.4 kg .

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3 years ago
What is the resistance of a bulb of 4ow<br>connected in a line of 220v?<br>2​
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1210 ohm

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Suppose you first walk 12.0 m in a direction 200 west of north and then 20.0 m in a direction 40.00 south of west. How far are y
Tpy6a [65]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

the compass direction of the resultant displacement is  \theta  =4.7^o south of west

Explanation:

Generally using cosine we can obtain the resultant R as follows

     R^2  =  A^2  + B^2 -2ABcos(70)

=>   R  =  \sqrt{12^2  + 20^2  - 2(12 ) *  (20) cos  70}

=>    R  =  19.48 \  m

We can obtain the direction of the resultant by first  using sine rule to obtain angle C as follows

       \frac{A}{sin  C}  =  \frac{R}{sin70 }

=>    C=  sin ^{-1} [\frac{A *  (sin 70)}{R} ]

=>    C =  sin ^{-1} [\frac{20 *  (sin 70)}{19.48} ]

=>  C =  74.7 ^o

Then the direction is obtained as

       \theta  =  C  -  70

=>    \theta  = 74.7   -  70

=>     \theta  =4.7^o

Hence the compass direction of the resultant displacement is  \theta  =4.7^o south of west

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