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2 years ago

Evaluate the expression when n=3

Mathematics

1 answer:

WARRIOR [948]2 years ago

8 0

The answer is 22. Work: n=3 and 3 to the second power would be 9 because 3x3=9 and 9+13=22. Hope I could help! Tell me if i’m wrong though!

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PLEASE HELP!!! Question is above^

julsineya [31]

Answer:

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 9, 2) and (x₂, y₂ ) = (- 4, 2)

d = $\sqrt{(-4+9)^2+(2-2)^2}$

= $\sqrt{5^2+0^2}$ = $\sqrt{25}$ = 5 → C

5 0

3 years ago

Frank received a monthly statement for his college savings account. It listed a deposit of $100 as +100.00. It listed a withdraw

artcher [175]

Answer:

Add: $100

Take Out: $25

Total: $835.50

Step-by-step explanation:

A deposit is an amount that is put into the account, by the owner or by someone else.

A withdrawal is an amount that is taken out of the account.

The overall ending balance shows the total amount in the account at the end of the month.

7 0

3 years ago

The rule which allows us to change the sign of an exponent is called the ____ rule.

Bogdan [553]

Answer:

The rule which allows us to change the sign of an exponent is called the negative exponent rule.

Step-by-step explanation:

Consider the provided information.

The negative exponent rule is the rule which allows to change the sign of an exponent.

$x^{-1}=\frac{1}{x}$

According to negative exponent rule: A negative exponents in the numerator moved to the denominator and become positive exponents.

If A negative exponents in the denominator moved to the numerator and become positive exponents.

Hence, the required statement is: The rule which allows us to change the sign of an exponent is called the negative exponent rule.

6 0

3 years ago

Gunther invested $10,000 in two mutual funds. One of the funds rose 6% in one year and the other rose 9% in one year. If his inv

mote1985 [20]

Answer:

$7200 in the fund rose 6% n $2800 in the fund rose 9%

Step-by-step explanation:

let x be the amount in the fund rose 6%

gain in one year=x*6%=0.06x

total amount is 10000

so amount in the fund rose 9% = 10000-x

gain in one year=(10000-x)*9%=900-0.09x

total gain=0.06x+900-0.09x=900-0.03x

=684

900-684=0.03x

0.03x=216

x=7200

the other fund amount=10000-7200=2800

5 0

3 years ago

Read 2 more answers

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago