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3 years ago

Write the equation of the line that passes through the point (-9,10) and is parallel to the y axis

Mathematics

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

Step-by-step explanation:

The equation of any line parallel to the y axis is y = y₀

where y₀ is the y-coordinate of any point from the line

(and the y-intercept of the line)

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-5x - 7 < 28

ArbitrLikvidat [17]

-5x - 7 < 28.....add 7 to both sides
-5x < 35....divide both sides by -5, change the inequality sign (u change the inequality sign when dividing/multiplying by a negative number)
x > -7

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3 years ago

Find the missing factor.<br> 200 x ____ = 600<br> A) 2<br> B) 3<br> C) 4<br> D) 5

kykrilka [37]

Answer:

B. 3

Step-by-step explanation:

we know 2x3 = 6 soo just add 2 zeros = 600

4 0

2 years ago

Read 2 more answers

Let f(x) = (5)^x+1 .Evaluate f (-3) without using a calculator

rewona [7]

Answer:

$f\left(-3\right)=\frac{126}{125}$

Step-by-step explanation:

Given

$f\left(x\right)\:=\:\left(5\right)^x+1$

Putting x = -3 to find f(-3)

$f\left(-3\right)\:=\:\left(5\right)^{\left(-3\right)}+1$

$5^{-3}=\frac{1}{125}$ ∵ $\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$f\left(-3\right)=\frac{1}{125}+1$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:1=\frac{1\cdot \:125}{125}$

$f\left(-3\right)=\frac{1\cdot \:\:125}{125}+\frac{1}{125}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$f\left(-3\right)=\frac{1\cdot \:\:125+1}{125}$

$f\left(-3\right)=\frac{126}{125}$ ∵ $1\cdot \:125+1=126$

Thus,

$f\left(-3\right)=\frac{126}{125}$

6 0

4 years ago

−3xy ^5 (8y) Simplified

german

-24xy^6 is that simplified

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3 years ago

The absolute value function, f(x) = –|x| – 3, is shown.

Elanso [62]

Answer: D. all real numbers less than or equal to –3

5 0

3 years ago