Explanation:
General electronic configuration for the given groups are as follows.
For 4A(14) : 
This means that there are 4 unpaired electrons in group 4A(14).
For 7A(17) : 
So, there are 7 unpaired electrons present in group 7A(17).
For 1A(1) : 
Hence, there is only one unpaired electron present in group 1A(1).
For 6A(16) :
So, there are 6 unpaired electrons present in group 6A(16).
Answer:
D. The ionic number.
Explanation:
Whenever an element losses or gains an electron; it becomes charged, thus turns to an ion. The ion can either be positively charged when it losses an electron or negarively charged when it gains an electron. The number shows the required number of electrons gained (negative) or lost (positive).
The molarity of KOH is 0.1055 M
<u><em> calculation</em></u>
Step 1: write the equation for reaction between H₂C₂O₄.2H₂O and KOH
H₂C₂O₄.2H₂O + 2 KOH → K₂C₂O₄ +4 H₂O
step 2: find the moles of H₂C₂O₄.2H₂O
moles = mass÷ molar mass
from periodic table the molar mass H₂C₂O₄.2H₂O= (1 x2) +(12 x2) +(16 x4) + 2(18)=126 g/mol
= 0.2000 g ÷ 126 g/mol =0.00159 moles
step 3: use the mole ratio to calculate the moles of KOH
H₂C₂O₄.2H₂O : KOH is 1:2
therefore the moles of KOH =0.00159 x 2 = 0.00318 moles
step 4: find molarity of KOH
molarity = moles/volume in liters
volume in liters = 30.12/1000=0.03012 L
molarity is therefore = 0.00318/0.03012 =0.1055 M
Because there to tiny to see
Answer:
ratio=0.996m/s
Explanation:
; M= molecular weight of compound;
RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.
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