Answer:
T₂ = 550.60 K
Explanation:
Given data:
Initial temperature = 16.3°C (16.3+273 = 289.3 K)
Initial pressure = 9.30 atm
Final temperature = ?
Final pressure = 17.7 atm
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
9.30 atm / 289.3 K = 17.7 atm/T₂
T₂ = 17.7 atm × 289.3 K / 9.30 atm
T₂ = 5120.61 atm. K /9.30 atm
T₂ = 550.60 K
I think the answer is C respiratory system
Answer:
1)Na2O
let the valency of Na is x
2(x)+(2)=0
2x+2=0
2x=-2
x=-1
2)ZnO
let the valency of Zn is x
x+2=0
x=-2
3)Al2O3
let the valency of Al is x
2(x)+3(2)=0
2x+6=0
2x=-6
x=-3
4)MgO
let the valency of Mg is x
x+2=0
x=-2
Moles= mass divided by Molecular mass
Moles= 251.4 divided by 84
Moles=2.99
Rounded up is 3