a. 6.0 L of H₂(g) at STP b. 12.0 L of CO₂(g) at STP c. 18.0 L of HCI(g) at STP d. 24.0 L of O₂(g) at STP
Answer:
Option-B is the correct answer.
Explanation:
As we know that any gas ( 1 mole) at standard temperature (273 K or 0 °C) and pressure (1 atm) occupies exactly 22.4 L of volume.
Therefore, at standard conditions 12 L of CH₄ containing 3.22 × 10²³ molecules will be equal to number of molecules (3.22 × 10²³) contained by 12 L of CO₂ as both the volumes are the same.
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Explanation: if you multiply the number of moles in the hydrogen atoms by the number of the once displayed and you multiply it by 3 and get the answer 6