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Aleks [24]
4 years ago
6

How many unpaired electrons are present in the ground state of an atom from each of the following groups?

Chemistry
1 answer:
Paha777 [63]4 years ago
3 0

Explanation:

General electronic configuration for the given groups are as follows.

For 4A(14) : ns^{2}np^{4}

This means that there are 4 unpaired electrons in group 4A(14).

For 7A(17) : ns^{2}np^{5}

So, there are 7 unpaired electrons present in group 7A(17).

For 1A(1) : ns^{1}

Hence, there is only one unpaired electron present in group 1A(1).

For 6A(16) : ns^{2}np^{4}

So, there are 6 unpaired electrons present in group 6A(16).

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Galactic is referring to the galaxy and cosmos! :)
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4 years ago
A 50.0-ml sample of 0.200 m sodium hydroxide is titrated with 0.200 m nitric acid. calculate the ph in the titration after you a
attashe74 [19]

Hey there!:

Concentration of NaOH = 0.200 M

Concentration of HNO₃= 0.200 M

Total volume =  50.0 mL + 60.0 mL = 110 mL=> 0.11 L

The neutralization reaction between  NaOH and HNO3 :

OH⁻  + H⁺  ---------->  H₂O

So :

n ( H⁺ ) = 60 mL * 0.200 M / 1000 mL  => 0.012 moles of H⁺

n ( OH⁻ ) = 50 mL 0.200 M / 1000 mL => 0.01 moles of OH⁻

Hence OH⁻ is limiting reagent  .

Remaining moles of  H⁺ = 0.012 - 0.01  =>  0.002 moles

Concentration of H⁺  = 0.002 M / 0.11 L

Concentration of H⁺ = 0.01818 moles/L

Therefore:

pH = - log [ H⁺ ]

pH = - log [ 0.01818 ]

pH = 1.74

Hope that helps!

7 0
3 years ago
Convert 1000dm to km​
polet [3.4K]

1000dm = 0.1 km

The picture below is proof that it is correct.

5 0
3 years ago
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Consider the following balanced equation. SiO2(s)+3C(s)→SiC(s)+2CO(g) Complete the following table, showing the appropriate numb
vlada-n [284]

Answer:

mol(SiO₂)              mol(C)               mol(SiC)                    mol(CO)

      3                          9                          3                                6

      1                           3                           1                                2

     13                         39                         13                             26

    2.5                        7.5                       2.5                            5.0

    1.4                         4.2                        1.4                            2.8

Explanation:

  • From the balanced equation:

<em>SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),</em>

  • It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.
  • We can complete the table of no. of moles of each component:

<u><em>1. 9.0 moles of C:</em></u>

We use the triple amount of C, so we multiply the others by 3.0.

So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.

<u><em>2. 1.0 mole of SiO₂:</em></u>

We use the same amount of SiO₂ as in the balnced equation, so the no. of moles of other components will be the same as in the balanced equation.

So, it will be 1.0 moles of SiO₂ with 3.0 moles of C that produce 1.0 moles of SiC and 2.0 moles of CO.

<u><em>3. 26.0 moles of CO:</em></u>

We use the amount of CO higher by 13 times than that in the balanced equation, so we multiply the others by 13.0.

So, it will be 13.0 moles of SiO₂ with 39.0 moles of C that produce 13.0 moles of SiC and 26.0 moles of CO.

<u><em>4. 7.5 moles of C:</em></u>

We use the amount of C higher by 2.5 times than that in the balanced equation, so we multiply the others by 2.5.

So, it will be 2.5 moles of SiO₂ with 7.5 moles of C that produce 2.5 moles of SiC and 5.0 moles of CO.

<u><em>5. 1.4 moles of SiO₂:</em></u>

We use the amount of SiO₂ higher by 1.4 times than that in the balanced equation, so we multiply the others by 1.4.

So, it will be 1.4 moles of SiO₂ with 4.2 moles of C that produce 1.4 moles of SiC and 2.8 moles of CO.

5 0
3 years ago
Pls hurry I need to have this ASAP
tankabanditka [31]

Answer:

The image is too blurry to see anything

Explanation:

Please upload a better image

3 0
2 years ago
Read 2 more answers
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