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3 years ago

PLEASE I HAVE 10 min TO FINISH THIS I NEED HELP

Mathematics

2 answers:

Allisa [31]3 years ago

8 0

An acute angle is 90 degrees

Brut [27]3 years ago

5 0

Answer:

Is an acute angle. Acute angle should be 90 degrees

Step-by-step explanation:

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Point C is located at (1, 2) and point D is located at (−4, −2). Find the y value of the point that is 1 over 4 the distance fro

fomenos

If we use similar triangles ( as shown in the attachment ) we will see that the line CM is also 1/4 *( yC-yD)= 1/4*(2+2) = 1/4*4 =1
Answer: y-value of that point is A) y=1.

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4 0

3 years ago

Read 2 more answers

What is the slope of the line shown below?<br><br> (9, 1) and (-3, -7

Dima020 [189]

Answer:

The slope is 4

Step-by-step explanation:

I think it's right

3 0

3 years ago

Can anyone help, I’ll give Brainly, I’m handing em out like nothing lol

finlep [7]

Answer:

2.5

Step-by-step explanation:

50 x $0.05 = 2.5

6 0

2 years ago

Read 2 more answers

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago

from the top of a tree the angle of depression of a rock on the ground is 49 degrees. If the tree is 18.5 m tall, how far is the

Rashid [163]

Answer:

Step-by-step explanation:

If you were to sit in the very top of said tree and look directly straight, your line of vision would be parallel to the ground. The angle of depression is in between your line of vision and the rock. When you look down at the rock, your line of vision to the rock is a transversal between the 2 parallel lines. With this being the case, the angle of depression is alternate interior with the angle made on the ground from the rock to the top of the tree. See the illustration I attached below.

We are looking for the distance on the ground between the tree and the rock, which we will call x. The side opposite the reference angle is the height of the tree and the side adjacent to the reference angle is x. Side opposite over side adjacent is the tangent ratio. Therefore,

$tan(49)=\frac{18.5}{x}$ and

$x=\frac{18.5}{tan(49)}$ and on your calculator in degree mode, you will find that

x = 16.08 m

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3 years ago