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KIM [24]
3 years ago
10

Best Answer Gets Brainliest Please help asap

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0
<h2>Answer:</h2>

[1] Area of base = 13 × 13 = 169in².

Area of faces = 4 (1/2 × 13 × 8) = 208in².

Surface area = (169 + 208)in² = 377in².

[2] Area of base = 1/2 × 5.2 × 4.5 = 11.7in².

Area of faces = 3 (√3/4 × 5.2²) = 35.1in².

Surface area = (35.1 + 11.7)in² = 46.8in².

[3] Area of base = 7 × 10 = 70in².

Area of faces = 2(1/2 × 7 × 6) + 2(1/2 × 10 × 4.8)

= 98in².

Surface area = (70 + 98)in² = 168in².

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What is 1234 ÷ 60?<br><img src="https://tex.z-dn.net/?f=1234%20%5Cdiv%2060" id="TexFormula1" title="1234 \div 60" alt="1234 \div
sineoko [7]
<h2>As a decimal: 20.56667</h2><h2>As fractions:  \frac{617}{30} OR    20\frac{17}{30}</h2>

3 0
3 years ago
12y+d=−19y+t solve for y?
sergij07 [2.7K]
Without values for the other variables, I assume you're asking for a literal equation.

12y+d=-19y+t
31y+d=t
31y=-d+t
y=(-d+t)/31
8 0
3 years ago
Read 2 more answers
Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a
ZanzabumX [31]

Answer:

1) Null hypothesis:p\geq 0.41  

Alternative hypothesis:p < 0.41

2) \hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) z_{crit}=-2.33

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017  

5) z_{crit}=-1.28

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that |t_{calculated}| so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis:p\geq 0.41  

Step-by-step explanation:

Data given and notation  

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

\hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

p_o=0.41 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area:  Null hypothesis:[tex]p\geq 0.41  

Alternative hypothesis:p < 0.41

Part 2  

\hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

z_{crit}=-2.33

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017  

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

z_{crit}=-1.28

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that |t_{calculated}| so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis:p\geq 0.41  

4 0
3 years ago
Which expression represents the distance between point (0, a) and point (a, 0) on a coordinate grid?
o-na [289]

Answer:

\sqrt{2} a

Step-by-step explanation:

The distance between point (x1,y1) and (x2,y2) on a coordinate plane is given by expression \sqrt{(x1-x2)^2+(y1-y2)^2}

In the problem given coordinate points are

(0, a) and (a, 0).

Thus, distance between these points are given by

distance = \sqrt{(x1-x2)^2+(y1-y2)^2}\\=>distance = \sqrt{(0-a)^2+(a-0)^2}\\=>distance = \sqrt{(a)^2+(a)^2}\\\\=>distance = \sqrt{2a^2}\\=>distance = \sqrt{2} a

Thus , expression \sqrt{2} a gives the distance between point (0, a) and point (a, 0) on a coordinate grid.

5 0
3 years ago
Read 2 more answers
3 times a number plus 5 is breathers than 12. Graph the possible solutions
Korolek [52]

3x12+5 is greater than 12 .

6 0
3 years ago
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