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3 years ago

The sun's energy is stored in fossil fuels. true or false.

1 answer:

8 0

Yes,suns original energy are still stored at the bonds of fossils in which they taken long,long time ago and these fossils powered now industries,fuel for vehicles.In those chemical bonds holds much energy packed together for centuries.

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A piece of warm concrete is placed in a cold-water tank, and energy flows between the concrete and the water. Which way does the

sammy [17]

Answer:

Heat flows from hot to cold objects. When a hot and a cold body are in thermal contact, they exchange heat energy until they reach thermal equilibrium, with the hot body cooling down and the cold body warming up. This is a natural phenomenon we experience all the time.

Explanation:

3 0

2 years ago

Because P and S waves travel faster through the Earth's mantle than through Earth's crust, scientists know that the mantle is __

larisa [96]

B. liquid and less denser

6 0

3 years ago

Read 2 more answers

The half-life of cobalt-60 is 5.26 years. If 50 g are left after 15.8 years, how many

PtichkaEL [24]

Answer:

400 g

Explanation:

The computation of the number of grams in the original sample is shown below:

Given that

half-life = 5.26 years

total time of decay = 15.8 years

final amount = 50.0 g

Now based on the above information

number of half-lives past is

= 15.8 ÷ 5.26

= 3 half-lives

Now

3 half-lives = 1 ÷ 8 remains = 50.0 g

So, the number of grams would be

= 50.0 g × 8

= 400 g

4 0

2 years ago

4. Which of the following is the term used to describe a body's resistance to a change in motion?

Alborosie

Inertia ..................

5 0

3 years ago

250 mL 0.1 M HCl solution is mixed with 250 mL

pishuonlain [190]

Answer:

The concentration of OH⁻ in the mixture is 0.05 M

Explanation:

The reaction of neutralization between HCl and NaOH is the following:

H⁺(aq) + OH⁻(aq) ⇄ H₂O(l)

The number of moles of HCl is:

$n_{HCl} = C*V = 0.1 mol/L*0.250L = 0.025 moles$

Similarly, the number of moles of NaOH is:

$n_{NaOH} = C*V = 0.2 mol/L*0.250L = 0.05 moles$

Now, from the reaction of HCl and NaOH we have the following number of moles of NaOH remaining:

$n_{NaOH} = 0.05 moles - 0.025 moles = 0.025 moles$

Finally, the concentration of OH⁻ in the mixture is:

$C =\frac{n_{NaOH}}{V_{T}}=\frac{0.025 moles}{0.250*2 L} = 0.05 moles/L$

Therefore, the concentration of OH⁻ in the mixture is 0.05 M.

I hope it helps you!

8 0

3 years ago