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Liono4ka [1.6K]
3 years ago
9

Why is it not necessary for radio telescope surfaces to be as smooth as a mirror?

Physics
1 answer:
Law Incorporation [45]3 years ago
8 0
It doesn't on account of radio waves are longer than optical waves. Radio waves are a sort of electromagnetic radiation with wavelengths in the electromagnetic range longer than infrared light. These long waves are in the radio locale of the electromagnetic range.
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What is the displacement from a starting position of (14.0, 3.0) m to a final position of (−3.0, −4.0) m?
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3 0
3 years ago
1. (30 pts) Let x(t) = cos(πt/2) be a continuous-time signal,
posledela

Given that the function of the wave is f(x) = cos(π•t/2), we have;

a. The graph of the function is attached

b. 4 units of time

c. Even

d. 4.935 J/kg

e. 1.234 W/kg

<h3>How can the factors of the wave be found?</h3>

a. Please find attached the graph of the signal created with GeoGebra

b. The period of the signal, T = 2•π/(π/2) = <u>4</u>

c. The signal is <u>even</u>, given that it is symmetrical about the y-axis

d. The energy of the signal is given by the formula;

\frac{1}{2}  \cdot  \mu^{2} \cdot \omega ^{2}  \cdot \:  {a}^{2}  \times  \lambda

Which gives;

E = 0.5 × 1.571² × 1² × 4 = <u>4.935 J/kg</u>

e. The power of the wave is given by the formula;

E = 0.5 × 1.571² × 1² × 4 × 0.25 = <u>1.234 W/</u><u>kg</u>

Learn more about waves here:

brainly.com/question/14015797

8 0
2 years ago
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