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irakobra [83]
3 years ago
8

Can someone help me with this function problem?

Mathematics
1 answer:
Stels [109]3 years ago
5 0
No because there are two of the same inputs(x) (2,5) and (2,7)
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Find the quadratic function that has the vertex (4,5) and passes through the point (8,21) If possible, can you explain the work?
Ganezh [65]
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!

8 0
3 years ago
Find the slope of the line (-3,-3) (1,1)
Volgvan

Answer: The slope is m = 1

Step-by-step explanation:

-To find the slope, you need the slope formula:

m=\frac{y2-y1}{x2-x1}  where you have (x1,y1) and (x2,y2) on the equation.

-Next, you put the two points to the equation:

m=\frac{1+3}{1+3}

-And then you solve the equation:

m=\frac{1+3}{1+3}

m=\frac{1+3}{1+3}  = \frac{4}{4}=1

m=1

5 0
3 years ago
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Step-by-step explanation:

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Using the measurements given below, find the hypotenuse of the triangle.
zloy xaker [14]

Answer:

In the triangle shown, AB = 11, BC = 61. Find AC. Right Triangle ABC v2. 3,600; 3,842; 60; 62. 4. Using the following measurements, find the length of the leg of the right triangle. leg = 5

Step-by-step explanation:

Not sure if that's helpful, but hope it is.

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Which name correctly classifies this triangle?
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