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sweet [91]
3 years ago
15

A middle school took all of its 6th grade students on a field trip to see a symphony at

Mathematics
1 answer:
butalik [34]3 years ago
4 0

Answer:

49%

Step-by-step explanation:

to get the percentage you put the number of occupied seats over total number of seats and multiply it by 100 over 1

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Estimate 137,638 to the nearest whole number
Tamiku [17]
The answer would be 140,000 :)
6 0
3 years ago
In what place is the 2 394.5012,
Naddik [55]

Answer:

Ten thousandths

Step-by-step explanation:

The 4 is in the ones place, so the 5 is in the tenths, the 0 in the hundredths, the 1 in the thousandths, so the 2 is in the ten thousandths.

8 0
3 years ago
Read 2 more answers
The picturre explains the question
Alina [70]

Answer:

x = 47°

Step-by-step explanation:

Since the two angles on a line add up to 180 degrees:

x = 180-133

x = 47°

3 0
3 years ago
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there are some nickles dimes and quaters in a large pinnhy bank for every 2 nickles there 3 dimes for every 2 dimes there five q
atroni [7]

100 nickels 150 dimes 250 quarters

Step-by-step explanation:

Trust me

4 0
2 years ago
Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°
Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

\angle OQR+\angle ORQ+\angle ROQ=180^o

Now, since the figure already shows that angle m\angle2+\angle ORQ+50^o=180^oNow, since we have established that the base angles m\angle2+m\angle2+50^o=180^owe can now solve the above equation for m<2 as follows:

\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}

Therefore, the correct answer is: option D

7 0
1 year ago
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