Answer:
0.00225 N/m
Explanation:
Parameters given:
Current in first wire, I(1) = 15A
Current in second wire, I(2) = 15A
Distance between two wires, R = 1cm = 0.01m
The force per unit length between two current carrying wires is:
F/L = μ₀I(1)I(2)/2πR
μ₀ = 4π * 10^(-7) Tm/A
F/L = [4π * 10^(-7) * 15 * 15] / (2π * 0.01)
F/L = 2.25 * 10^(-3) N/m or 0.00225 * 10^(-3) N/m
Answer:
melanie ran 8.3 meters per second
Explanation:
I think thats right, hope it helps.
Answer:
The person will travel 24 meters.
Explanation:
Distance = Rate * TIme
Distance = d = ?
Rate = r = 6 m/s
Time = t = 4 seconds
d = r*t = (6 m/s)*(4 seconds)
d = 24 m
**Note that the units (m/s) and (s/1) cancel to leave the answer in meters, the desired unit**
Answer:
The angle of refraction is option b: 17°.
Explanation:
We can find the angle of refraction by using Snell's law:
Where:
n₁: is the index of refraction of the medium 1 (air) = 1.0003
n₂: is the index of refraction of the medium 2 (diamond) = 2.42
θ₁: is the angle of incidence = 45°
θ₂: is the angle of refraction =?
Hence, the angle of refraction is:
Therefore, the correct option is b: 17°.
I hope it helps you!
The object with the greater mass should be attached to the spring with the smaller spring constant, so that the resulting spring-object system has the greatest possible period of oscillation.
Answer: Option D
<u>Explanation:
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According to the simple harmonic motions, from physics, it gives a relation between deformation force and the deflection. The more deflection results in more time period of oscillation.
F = - k x
where ‘k’ is the spring constant, and ‘F’ is the deformation force.
So, deflection is directly proportionate to forces, and inversely proportionate to its spring constant. Hence, we can derive that the force must be maximum, and hence weight must be maximum, with the spring constant lesser. Then, the deflection will be high. So, time period increases.