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In-s [12.5K]
3 years ago
5

Please please please please help soon!!

Physics
1 answer:
GarryVolchara [31]3 years ago
6 0
This is so easy freezing and boiling, are you in 4th?
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Work and Energy
Sergeeva-Olga [200]

a) W_1 = 2332 J, W_2= 2332 J

The work done by the student in each trial is equal to the gravitational potential energy gained by the student:

W=mg\Delta h

where

m = 68 kg is the mass of the student

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the gain in height of the student

For the first student, \Delta h = 3.5 m, so the work done is

W_1 = (68)(9.8)(3.5)=2332 J

The second student runs up to the same height (3.5 m), so the work done by the second student is the same:

W_2 = (68)(9.8)(3.5)=2332 J

2) P_1 = 204.6 W, P_2 = 274.4 W

The power exerted by each student is given by

P=\frac{W}{t}

where

W is the work done

t is the time taken

For the first student, W_1 = 2332 J and t=11.4 s, so the power exerted is

P_1 = \frac{W_1}{t_1}=\frac{2332 J}{11.4 s}=204.6 W

For the second student, W_2 = 2332 J and t=8.5 s, so the power exerted is

P_2 = \frac{W_2}{t_2}=\frac{2332 J}{8.5 s}=274.4 W

5 0
3 years ago
In the graph below, why does the graph stop increasing after 30 seconds?
stepladder [879]

Answer:

The answer is "Option C".

Explanation:

It's evident from the figure below that after thirty minutes, not no more hydrogen can be created because all of the reactants have converted into products.

hydrogen gas created in cm cubes per period x = 20 seconds, y = 45 centimeters squared, and so on.

A reaction's terminus (the graph's flat line) indicates that no further products are being created during the reaction.

6 0
3 years ago
Identify the following joint
MissTica

This is a ball and socket joint.

7 0
3 years ago
Calculate the acceleration of a skier heading down a 10.0º slope, assuming the coefficient of friction for waxed wood on wet sno
lutik1710 [3]

(a) 0.74 m/s^2

Explanation:

There are two forces acting on the skier: the component of the weight parallel to the slope, which acts downward, and the frictional force, which acts upward along the incline.

The component of the weight parallel to the inclined plane is:

W= m g sin \theta

where m is the mass of the skier, g=9.81 m/s^2 and \theta=10^{\circ}.

The frictional force is instead

F_f = -\mu m g cos \theta

\mu=0.1 is the coefficient of friction for waxed wood on wet snow.

If we apply Newton's second law, we can write that the net force must be equal to the product of mass per acceleration:

mgsin \theta -\mu mg cos \theta =ma

And symplifying m, we can find the acceleration:

a=g sin \theta-\mu g cos \theta=

=(9.81 m/s^2)(sin 10^{\circ})-(0.1)(9.81 m/s^2)(cos 10^{\circ})=0.74 m/s^2


(b) 5.7^{\circ}

Explanation:

This time, the skier is moving at constant velocity. Therefore, the acceleration is zero (a=0) and Newton's second law becomes:

mg sin \theta - \mu m g cos \theta=0

By simplifying, we get

tan \theta = \mu

From which we can find the angle at which the skier could coast at a constant velocity:

\theta= tan^{-1} (\mu) = tan^{-1} (0.1)=5.7^{\circ}



6 0
3 years ago
A tea kettle is warmed on an electric stove. After a while, water vapor builds inside the kettle and causes a whistle in the lid
Artemon [7]
The first law of thermodynamics states that energy can neither be created nor destroyed, but it can be converted from one form to another form.
The electric stove is supplying heat to the kettle, this makes the water particles in the kettle to gain more kinetic energy and to increase their motion until they gather enough energy to turn to vapor. The energy gained by the water particles is used to carry out the work of whistling of the kettle.
6 0
4 years ago
Read 2 more answers
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