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3 years ago

PLEASE HELP ME ASAP!!!

Mathematics

1 answer:

nasty-shy [4]3 years ago

3 0

Answer:

1.1r,-1r

2.-2x,5x

Step-by-step explanation:

i tgink tgis is what the answer os unless i am a doing the math wrong. so i hope im right and tgis helps

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PLS HELPP <br>pls answer all! pls show work <br>

ICE Princess25 [194]

Answer: middle one = 4/4 + 1 + 2 =3

Step-by-step explanation:

4/4 also equals one so x=4 1+2=3

4/4=1

7 0

3 years ago

1) the point where the x abd y axis meet 2) if m< A + m<D = 90, then <A and D are ____ angles 3) an angle formed by opp

Brums [2.3K]

1. The point where x and y axis meet is the intersect, origin of the coordinate system (0,0)

2. m<A and m<D = 90 then <A and D are complementary angles

3. 180 angle or linear rays

4. Obtuse angle measure more than 90

5. Segment of equal lengths are congruent segments

6. Lines that meet at a 90 angle are perpendicular

8 0

3 years ago

A rectangular prism with length width and heighth has a volume of two

kobusy [5.1K]

Answer:

9m3

Step-by-step explanation:

multiply every thing if the answer is not satisfactory its because there is a bunch of info losing

7 0

3 years ago

1. In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and (-3,-5) lie? Verify your answer b

pashok25 [27]

Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) lies in the 3rd quadrant

Step-by-step explanation:

Let us revise the signs of the coordinates in each quadrant

x and y coordinates are positive in the 1st quadrant
x-coordinate is negative and y-coordinate is positive in the 2nd quadrant
x and y coordinates are negative in the 3rd quadrant
x-coordinate is positive and y-coordinate is negative in the 4th quadrant
The general point on the positive part of x-axis is (x , 0), and on the negative part of x-axis is (-x , 0)
The general point on the positive part of y-axis is (0 , y), and on the negative part of y-axis is (0 , -y)

Now let us check the points

Point (-2 , 4) ⇒ red point

∵ x = -2 and y = 4

∵ x-coordinate is negative and y-coordinate is positive

∴ Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) ⇒ blue point

∵ x = 3 and y = -1

∵ x-coordinate is positive and y-coordinate is negative

∴ Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) ⇒ green point

∵ x = -1 and y = 0

∵ x-coordinate is negative and y-coordinate is zero

∴ Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) ⇒ purple point

∵ x = 1 and y =2

∵ x and y coordinates are positive

∴ Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) ⇒ black point

∵ x = -3 and y = -5

∵ x and y coordinates are negative

∴ Point (-3 , -5) lies in the 3rd quadrant

<em>Look to the attached graph for more understand</em>

Learn more:

You can learn more about the four quadrant in brainly.com/question/9381523

#LearnwithBrainly

5 0

3 years ago

Suppose that IQ scores have a bell-shaped distribution with a mean of 104 and a standard deviation of 17. Using the empirical ru

Shalnov [3]

Answer:

By the Empirical Rule, 68% of IQ scores are between 87 and 121

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 104

Standard deviation = 17

Using the empirical rule, what percentage of IQ scores are between 87 and 121

87 = 104 - 1*17

So 87 is one standard deviation below the mean

121 = 104 + 1*17

So 121 is one standard deviation above the mean

By the Empirical Rule, 68% of IQ scores are between 87 and 121

4 0

4 years ago