Answer:
18 terms
Step-by-step explanation:
The first given sequence has first term a1=2 and common difference d=5. Its explicit formula is ...
an = 2 +5(n -1) = 5n -3
We want the n-th term of this sequence to be the same as the n-th term of the sequence defined by ...
an = 4n +15
We can find n that makes this true by setting the 'an' values equal:
an = an
5n -3 = 4n +15
n = 18 . . . . . . . . . . add 3-4n
The number of terms in each sequence is 18.
_____
<em>Additional comment</em>
The last term in each sequence is 87.
The answer is the 3x divided by 3 = -12 divided by 3
Answer:
55/28 hours/day (approx. 1.96 hours/day)
Step-by-step explanation:
9 1/6 hours / 4 2/3 days
= 55/6 hours / 14/3 days
= 55/6 * 3/14 hours/day
= 55/28 hours/day
(approx. 1.96 hours/day)
Answer:
2√2
Step-by-step explanation:
We can find the relationship of interest by solving the given equation for A, the mean distance.
<h3>Solve for A</h3>

<h3>Substitute values</h3>
The mean distance of planet X is found in terms of its period to be ...

The mean distance of planet Y can be found using the given relation ...

The mean distance of planet Y is increased from that of planet X by the factor ...
2√2