Answer:
<20,23>
Step-by-step explanation:
u= <4,5> and v= <0,-1>
2v = 2*<0,-1> = <0,-2>
5u = 5* <4,5> = <20,25>
2v+5u = <0,-2> + <20,25>
= <20,23>
Answer: 4x = -8
Reasoning:
Multiply both sides by 4
Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.
so.. that'd be the V(x) for such box, now, where is the maximum point at?
now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.
so, the volume will then be at
Let time be x distance be y
Put value in eq(2)
Put it in eq(1)
Answer: Simplify 8/10 which is 4/5.
Step-by-step explanation: