Answer:
I don't know
Step-by-step explanation:
How you will find out the value of 'n ' ?
[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]
There would be 1 real zero and two complex zeros
If you would like to solve 1/3 / 6, you can do this using the following steps:
1/3 / 6 = 1/3 / 6/1 = 1/3 * 1/6 = 1/18
The correct result would be 1/18.
Yurrr can i please have it