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Nezavi [6.7K]
3 years ago
8

Find the quotient: 17 ÷ 3 2/5 Find the quotient: 5 1/7 ÷ 3

Mathematics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

1. =5

2. =1 5/7

Step-by-step explanation: Hope this help :D

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There are 1644 students in central high school. There are 50 more girls then boys. How many boys are there ?
forsale [732]

The answer is 797 boys

1644÷2-50÷2=797

5 0
3 years ago
280 is 72% of what number?
IgorLugansk [536]

Answer:

389

Step-by-step explanation:

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5 0
2 years ago
Thank you for the help! I would appreciate it if someone could explain this content to me. I need help on both of them. I wish t
maksim [4K]
I'm not 100% sure if I am right, but for number 9 you would pick two points on , let's just say you pick points (0, 1) and (2, -2). Then you would find those points in the table. So in this case the answer would be D. And I'm not really sure how to explain #10 but you basically work out each problem with the graph to see if it makes sense. For example if you try working out problem F it wouldn't make sense since you start of with 10 dollars and earn 2 each day. But on the graph it shows that you are loosing two. Sorry if I didn't explain it right, if you have more questions let me know!
5 0
3 years ago
The black graph is the graph of y=f(x). Choose the equation for the red graph.<br> Please Help me!!
katen-ka-za [31]

Answer:

c

Step-by-step explanation:

The red graph is the black graph translated vertically by 1 unit

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Thus f(x) + 1

Note

y - 1 = f(x) ← add 1 to both sides

y = f(x) + 1 ← as required

The equation of the red graph is

y - 1 = f(x) → c

4 0
3 years ago
Find the equation of the line that passes through (1, -1) and is parallel to
daser333 [38]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1

8 0
3 years ago
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