In guinea pigs, the short hair trait is dominant. If two heterozygous guinea pigs were crossed, what would be the phenotypes of
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Answer:
Thus, the minimum number of photons per second is 77.34
Explanation:
Light intensity, =
Pupil has a diameter, d = 8.5 mm
= 8.5 x m
Radius of the eye, r = 4.25 x m
∴ Area of the eye, A =
=
=
Let be the minimum number of photons.
Therefore, =
x A
= x
= W
Thus the minimum number of photons is given by
where E =
=
=
Therefore, =
= 77.34 photons per second
Thus, the minimum number of photons per second is 77.34