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Akimi4 [234]
3 years ago
10

A student pushes a box across the floor using 8w of power in 7 seconds how much work does the student do

Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0

Answer:

Workdone = 56 Joules

Step-by-step explanation:

Given the following data;

Power = 8 watt

Time = 7 seconds

To find the workdone;

The workdone by an object or body is given by the formula;

Workdone = power * time

Workdone = 8 * 7

Workdone = 56 Joules.

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a.

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The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.

w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9

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b.

The polynomial y^2-10y+23 cannot be factored

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Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.

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