Ask question

Ask question

All categories

3 years ago

7

No esporte coletivo, um dos principais fatores desenvolvidos é o desenvolvimento social. Qual desses não faz parte das virtudes

ensinadas no esporte?
Companheirismo
Humildade
Ser justo (Fair Play)
Vencer independente do que precise ser feito

1 answer:

zvonat [6]3 years ago

4 0

Answer:

fair palybtgshsisuehdh

You might be interested in

the resistivity of gold is 2.44×10−8Ω⋅m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a cur

cricket20 [7]

Answer:

0.03605 V/m is the electric field in the gold wire.

Explanation:

Resistivity of the gold = $\rho = 2.44\times 10^{-8} \Omega.m$

Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)

Diameter of the wire = d = 0.9 mm

Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm = $0.45\times 0.001 m$

( 1mm = 0.001 m)

Area of the cross-section = $A=\pi r^2=\pi r^(0.45\times 0.001 m)^2$

Resistance of the wire = R

Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)

$R=\rho\times \frac{L}{A}$

$V(voltage)=I(current)\times R(Resistance)$ ( Ohm's law)

$\frac{V}{I}=\rho\times \frac{L}{A}$

We know, Electric field is given by :

$E=\frac{dV}{dr}$

$E=\frac{V}{L}$

$E=\frac{V}{L}=\rho\times \frac{I}{A}$

$E=2.44\times 10^{-8} \Omega.m\times \frac{0.940 A}{\pi r^(0.45\times 0.001 m)^2}=0.03605 V/m$

0.03605 V/m is the electric field in the gold wire.

3 0

4 years ago

What is the primary function of the small intestines

ikadub [295]

Digestion and Absorbtion

7 0

3 years ago

Astrology is considered a science because it is grounded in scientific research.<br>

erma4kov [3.2K]

Astrology is not science, it bases itself on twelve zodiac signs, astronomy however studies many phenomena in space in order to figure out how we came to be

7 0

3 years ago

Read 2 more answers

How do igneous rocks form??

pickupchik [31]

Magma that cools and forms

6 0

3 years ago

Read 2 more answers

A circuit consists of a 9.0 v battery connected to three resistors (52 , 17 , and 140 ) in series. (a) find the current that flo

Fudgin [204]

A) TOTAL Resistance = 41+18+120 = 179 ohms
<span>Current = V/R = 9 / 179 = 0.0503 A = 50.3 mA </span>

<span>B) V = I*R = .0503 * 41 = 2.06 V </span>

<span>C) V = I*R = .0503 * 18 = 0.91 V </span>

<span>D) V = I*R = .0503 * 120 = 6.03 V</span>

7 0

4 years ago