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fiasKO [112]
3 years ago
12

What is an event horizon? Does our Sun have an event horizon around it?

Physics
1 answer:
STatiana [176]3 years ago
6 0

Answer:

The event horizon of a black hole can be thought of either as the place around the black hole where the speed you need to escape becomes greater than the speed of light or as the place where the warping of spacetime around a collapsed star becomes so great that all straight lines pointing outward actually become curved paths bringing you back in. Only black holes have event horizons, so our Sun, which is a star in happy main-sequence equilibrium, cannot have one.

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A flywheel in the form of a uniformly thick disk of radius 1.33 m1.33 m has a mass of 70.6 kg70.6 kg and spins counterclockwise
ladessa [460]

Answer:

The constant torque required to stop the disk is 8.6 N-m in clockwise direction .

Explanation:

Let counterclockwise be positive direction and clockwise be negative direction .

Given

Radius of disk , r = 1.33 m

Mass of disc , m = 70.6 kg

Initial angular velocity , \omega_i =217 rpm

Final angular velocity , \omega_f =0\, rpm

Time taken to stop , t = 2.75 min

Let \alpha  be the angular acceleration

We know

\omega _f=\omega _i+\alpha t

=>0=217+2.75\alpha =>\alpha = -78.9\frac{rev}{min^{2}}

=>\alpha =-\frac{78.9\times 2\pi}{60\times 60}\frac{rad}{s^{2}}=-0.138 \frac{rad}{s^{2}}

Torque required to stop is given by

\tau =I\alpha

where  moment of inertia , I=\frac{mr^{2}}{2}=\frac{70.6\times 1.33^{2}}{2}kg.m^{2}=62.5 kg.m^{2}

=>\therefore \tau =-0.138\times 62.5\, N.m=-8.6\, N.m

Thus the constant torque required to stop the disk is 8.6 N-m in clockwise direction .

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Answer:

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