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FromTheMoon [43]
3 years ago
11

Jumping up is work against gravity why​

Physics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

gravitational force attract us towards the ground

Explanation:

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Based on the law of conservation of energy, which statement is false?
il63 [147K]

Answer:

A

A. Energy is lost when machines don't work right.

4 0
3 years ago
_____ variables are manipulated by the experiments
nikitadnepr [17]

Answer:

dependent variables

Explanation:

dependent varibeles are the thing you're measuring and independent variables are the thing you change in the exeriment to get a different dependent variable.

may I get brainliest please? :)

3 0
4 years ago
An engine has an energy input of 125 J, and 35 J of that energy is transformed into useful energy. What is the efficiency of the
xeze [42]

The efficiency of the engine at the given useful energy and input energy is 28%.

The given parameters:

  • <em>Input energy of the engine, = 125 J</em>
  • <em>Useful energy of the engine, 35 J</em>

The efficiency of the engine is defined as the ratio of the output energy (useful energy) to the input energy and it is calculated as follows;

efficiency\ = \frac{0ut put \ energy}{1nput \ energy} \times \ 100\%\\\\efficiency\ = \frac{35}{125} \times 100\%\\\\efficiency\ = 28 \ \%

Thus, the efficiency of the engine at the given useful energy and input energy is 28%.

Learn more about efficiency of engine here: brainly.com/question/6751595

7 0
2 years ago
A stereo speaker is placed between two observers who are 35 m apart, along the line connecting them. If one observer records an
kompoz [17]

Answer:

   x = 2,864 m ,       Ra = 32.1 m                       

Explanation:

Let's solve this problem in parts, let's start by finding the intensity of the sound in each observer

observer A β = 64 db

             β = 10 log Iₐ / I₀

where I₀ = 1 10⁻¹² W / m²

              Iₐ = I₀ 10 (β/ 10)

let's calculate

              Iₐ = 1 10⁻¹² (64/10)

              Iₐ = 2.51 10⁻⁶ W / m²

Observer B β = 85 db

             I_b = 1 10-12 10 (85/10)

             I_b = 3.16 10⁻⁴ W / m²

now we use that the emitted power that is constant is the intensity over the area of ​​the sphere where the sound is distributed

              P = I A

therefore for the two observers

              P = Ia Aa = Ib Ab

the area of ​​a sphere is

               A = 4π R²

we substitute

               Ia 4pi Ra2 = Ib 4pi Rb2

               Ia Ra2 = Ib Rb2

Let us call the distance from the observer be to the haughty R = ax, so the distance from the observer A to the haughty is R = 35 ax; we substitute

             Ia (35 -x) 2 = Ib x2

we develop and solve

           35-x = Ra (Ib / Ia) x

           35 = [Ra (Ib / Ia) +1] x

           x (11.22 +1) = 35

           x = 35 / 12.22

            x = 2,864 m

This is the distance of observer B

The distance from observer A

            Ra = 35 - x

            Ra = 35 - 2,864

            Ra = 32.1 m

8 0
3 years ago
A force exerted over a distance to move an object is?
Inessa [10]
Force= distance/time
Maybe that formula will help
4 0
3 years ago
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