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crimeas [40]
3 years ago
14

The image shows copper wire coiled around an iron nail and connected to a battery to create an electromagnet. Which factors dete

rmine the strength of this electromagnet? A. the voltage of the battery and the size of the switch B. the number of coils of wire around the nail and the length of the wire in the circuit C. the size of the nail and the size of the switch. D. the amount of electric current and the number of wire coils around the nail
Physics
1 answer:
allochka39001 [22]3 years ago
6 0

The amount of electric current in the coil and the number of turns of wire
in the coil directly determine the strength of the electromagnet.

But the voltage of the battery determines the amount of current through
the wire, so the battery voltage is also indirectly involved.


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Which substances are inorganic? Check all that apply.
bezimeni [28]

The major characteristic an organic compound has which an inorganic

compound doesn't  have is the presence of carbon atoms in the molecule.

This helps us to differentiate the compounds into their respective divisions.

Inorganic compounds

  • K2CO3
  • Fe3O4

Organic compounds

  • C6H12O6
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We can observe that inorganic compounds lack carbon atoms which makes

the answer valid.

Read more about inorganic compounds on brainly.com/question/2169750

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2 years ago
Many Fad Diets Discourage people from eating certain foods, leading to___
ANEK [815]

Answer:

I'm sure it's Nutritional Imbalance

Explanation:

7 0
3 years ago
Water is flowing in a pipe with a circular cross section but with varying cross-sectional area, and at all points the water comp
slamgirl [31]

(a) 5.66 m/s

The flow rate of the water in the pipe is given by

Q=Av

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

Here we have

Q=1.20 m^3/s

the radius of the pipe is

r = 0.260 m

So the cross-sectional area is

A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2

So we can re-arrange the equation to find the speed of the water:

v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s

(b) 0.326 m

The flow rate along the pipe is conserved, so we can write:

Q_1 = Q_2\\A_1 v_1 = A_2 v_2

where we have

A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s

and where A_2 is the cross-sectional area of the pipe at the second point.

Solving for A2,

A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2

And finally we can find the radius of the pipe at that point:

A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m

6 0
3 years ago
a large heavy truck and a baby carriage roll down a hill. Neglecting friction, at the bottom of the hill, the baby carriage will
Lisa [10]

Answer:

please give me brainlist and follow

Explanation:

At the bottom of the hill, the baby carriage will likely have less momentum Therefore, option D is correct. Solution: ... Therefore, at the bottom of the hill, the heavy truck will have more momentum and baby carriage will have less momentum.

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Which of the following activities belongs on the top of the physical activity for pyramid
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Playing Vedio Games. :)
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