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alukav5142 [94]
2 years ago
11

4. find the value of ‘k’ for which 2x 3y = 4 and (k 2) x 6y = 3k 2 has a infinitely many solutions.

Mathematics
1 answer:
Lana71 [14]2 years ago
7 0

For the given system of linear equations to give an infinite number of solutions the value of k should be 2.

<h3>What is a Dependent Consistent System of equations?</h3>

A system of the equation to be a Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

Given the two systems of linear equations,

2x + 3y = 4

(k+ 2)x + 6y = 3k+2

For any system of equations to have infinitely many solutions, the equation of the linear system must be in ratio, so that the lines of the equations overlap each other. Therefore, the ratio for the two of the given equations can be written as,

2/(k+2) = 3/6 = 4/(3k+2)

Solving the ratio to get the value of k,

2/(k+2) = 3/6

2/(k+2) = 1/2

2 × 2 = 1 × (k+2)

4 = k + 2

4 - 2 = k

k = 2

Hence, for the given system of linear equations to give an infinite number of solutions the value of k should be 2.

Learn more about the System of equation here:

brainly.com/question/12895249

#SPJ1

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A) if 18 muffins = 1 box,
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8 0
2 years ago
A pack of 13 candles is priced at $78. At that rate, how much would only 10 candles cost?
Sphinxa [80]

Answer:

78/13 = 6 (is the price of one candle)

6(price) x 10(candles) =60 is the answer

Hope it helped

8 0
3 years ago
Find the circumference of the given circle. Use 3.14 for pi, and round your answer to the nearest tenth.
N76 [4]

Answer:

59

Step-by-step explanation:

Because multiply 18.8 and 3.14 and get a number with a decimal so round up and get 59 :)

7 0
3 years ago
Let a = x2 + 4Rewrite the following equation in terms of a and set it equal to zero (x2+4)2+32=12x2+48
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Answer:

x^4 - 4x^2 = 0

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4 0
3 years ago
Find the simplified product:<br> sqrt 2x^2 * sqrt18^5
makvit [3.9K]

Answer:

1944x^2.

Step-by-step explanation:

sqrt 2x^2 * sqrt18^5

= sqrt2x^2 * (sqrt(9^5*2^5))

= sqrt 2 x^2 * (sqrt9^5 * sqrt 2^5)

= sqrt2 x^2 * (243* sqrt2^5)

= 2^0.5 (243 * 2^2.5) x^2

= 2^3 * 243 x^2

= 1944x^2.

5 0
2 years ago
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