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alukav5142 [94]
2 years ago
11

4. find the value of ‘k’ for which 2x 3y = 4 and (k 2) x 6y = 3k 2 has a infinitely many solutions.

Mathematics
1 answer:
Lana71 [14]2 years ago
7 0

For the given system of linear equations to give an infinite number of solutions the value of k should be 2.

<h3>What is a Dependent Consistent System of equations?</h3>

A system of the equation to be a Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

Given the two systems of linear equations,

2x + 3y = 4

(k+ 2)x + 6y = 3k+2

For any system of equations to have infinitely many solutions, the equation of the linear system must be in ratio, so that the lines of the equations overlap each other. Therefore, the ratio for the two of the given equations can be written as,

2/(k+2) = 3/6 = 4/(3k+2)

Solving the ratio to get the value of k,

2/(k+2) = 3/6

2/(k+2) = 1/2

2 × 2 = 1 × (k+2)

4 = k + 2

4 - 2 = k

k = 2

Hence, for the given system of linear equations to give an infinite number of solutions the value of k should be 2.

Learn more about the System of equation here:

brainly.com/question/12895249

#SPJ1

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Find the area of a rectangle that has a length of (x - 5) and a width of (3x + 1).
avanturin [10]

Answer:

A=3x^2 -14x -5

Step-by-step explanation:

(x-5)(3x+1)

3x^2 +x -15x -5

3x^2 -14x -5

5 0
3 years ago
6th grade math help me pleaseeee...
iren2701 [21]

Answer:

-3.8

Step-by-step explanation:

u = 3.8

u × -1 = 3.8 × -1

-u = -3.8

3 0
3 years ago
Find angle abc (2x+14) (x+7)
melisa1 [442]
It's a complementary angle, so just solve for x and subtract the CBD from 90, 
First, we have to solve for x.
2x + 14 + x + 7 = 90
Combine like terms
3x + 21 = 90
Balance, subtract 21 from each side.
3x = 69
Divide 3 from each side
x = 23.
So know that we know x is 23, we can go about it 2 ways, subtracting the other angle with 90 or just substituting the variable, I'd just substitute the variable for it so just do 23 + 7. That equals 30, angle ABC = 30.


7 0
3 years ago
Read 2 more answers
In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
3 years ago
- 4 -( -6) <br><br> 7 - (-4) <br><br> thank you to who ever solves it
fomenos
-4-(-6) = 2
7-(-4) = 11
5 0
3 years ago
Read 2 more answers
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