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klemol [59]
3 years ago
12

What is the distance between the endpoints of the beams p and q? 3.2 inches 3.7 inches 4.2 inches 4.4 inches open study?

Mathematics
1 answer:
Ulleksa [173]3 years ago
7 0
.5 inch, .5 inch, and .2 inch
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PLSSSSSSSSSSSSSSSSSSSSSS HELPPPPPPPPPPPPPPPPPPPPPPPPPPPP​
fgiga [73]

Answer:

17925

Step-by-step explanation:

3(1/4)=3.25

simple interest formula:

PV(1+it)=FV

we will divide the 72 months to convert it into years

72/12=6

15000(1+.0325*6)=17925

7 0
3 years ago
Read 2 more answers
What is the best estimate of 2π²?
Rasek [7]
2π^2=19.7392088 to 20 since 19.7392088 is closer to 20.
6 0
3 years ago
I need the answer to this question
bija089 [108]
If you divide the original equation by "a", you have your answer.
  30/a = (a*60)/a = 60*(a/a)
  30/a = 60
7 0
3 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
A radio station requires DJs to play 2 commercials for every 10 songs they play.What is the unit rate of songs to commercial?
slavikrds [6]
The correct answer for this question is that the unit rate is 5:1. We can work this out by simplifying down the 2 commercials to every 10 songs ration, so that 10:2 becomes 5:1. We can work this out by halving the original ratio to simplify it.
5 0
3 years ago
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