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klemol [59]
3 years ago
12

What is the distance between the endpoints of the beams p and q? 3.2 inches 3.7 inches 4.2 inches 4.4 inches open study?

Mathematics
1 answer:
Ulleksa [173]3 years ago
7 0
.5 inch, .5 inch, and .2 inch
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10 chunks of Swiss cheese total weight
Stels [109]
7.5 pounds of Swiss cheese, WOW

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3 years ago
Help is appreciated. Question is worth 15 points.<br><br> Suppose that 2
GrogVix [38]

Answer:

huh

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The figure is made up of a hemisphere and a cylinder.
Goryan [66]
Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: \pi \approx 3.14
V (volume) = ?

Solving:(<span>Cylinder volume)
</span>V = h* \pi *r^2
V = 8*3.14*5^2
V = 8*3.14*25
\boxed{ V_{cylinder}  = 628\:cm^3}

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4 * \pi *  \frac{r^3}{3}, but we have a hemisphere, so the formula will be half the volume of the hemisphere V =  \frac{1}{2}  * 4 * \pi *  \frac{r^3}{3} &#10;

Formula: (<span>Volume of the hemisphere)
</span>V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}

Solving:
V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}
V =  \frac{1570}{6}
\boxed{V_{hemisphere}\approx 261.6\:cm^3}


<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
Read 2 more answers
9y+11z+7y−4z
slava [35]
Answer is <span>16y + 7z

</span><span><span><span><span>9y</span>+<span>11z</span></span>+<span>7y</span></span>−<span>4z

</span></span><span>=<span><span><span><span><span>9y</span>+<span>11z</span></span>+<span>7y</span></span>+</span>−<span>4z

</span></span></span>Combine Like Terms:

<span>=<span><span><span><span>9y</span>+<span>11z</span></span>+<span>7y</span></span>+<span>−<span>4z

</span></span></span></span><span>=<span><span>(<span><span>9y</span>+<span>7y</span></span>)</span>+<span>(<span><span>11z</span>+<span>−<span>4z</span></span></span>)

</span></span></span><span>=<span><span>16y</span>+<span>7z</span></span></span><span>
</span>
7 0
3 years ago
Find the perimeter of this semi-circle with diameter, d = 18cm. Give your answer as an expression in terms of pi.
OLga [1]

Answer:

The perimeter of the given semi-circle in terms of \pi is

P=9\pi cm

Step-by-step explanation:

Given that the diameter of the semi-circle is 18cm

That is d=18cm

Therefore radius r=\frac{d}{2}

r=\frac{18}{2}

Therefore radius r=9cm

To find the perimeter of the semi-circle :

perimeter of the semi-circleP=\pi r

P=\pi\times 9 cm (where r=9 cm )

P=9\pi cm

The perimeter of the given semi-circle in terms of \pi is

P=9\pi cm

8 0
2 years ago
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