What is the value of the expression x^-2y^3 when x= -5 and y= 2
1 answer:
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Answer:
We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs
Step-by-step explanation:
We have the following info given by the problem
Subject 1 2 3 4 5 6 7
Drug A 6 3 4 5 7 1 4
Drug B 5 1 5 5 5 2 2
x=value for drug A , y = value for drug B
x: 6 3 4 5 7 1 4
y: 5 1 5 5 5 2 2
We want to verify if the mean response differs between the two drugs then the system of hypothesis for this case are:
Null hypothesis:
Alternative hypothesis:
We can begin calculating the difference and we obtain this:
d: -1, -2, 1, 0, -2, 1, -2
Now we can calculate the mean difference
Now we can find the the standard deviation for the differences, and we got:
And now we can calculate the statistic given by :
Now we can find the degrees of freedom given by:
We can calculate the p value, since we have a two tailed test the p value is given by:
We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs