Answer:
98
Step-by-step explanation:
As it is a little bit of a few questions about the other one I have to the store go back tomorrow and will get back tomorrow and I have been working
I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
let the other leg be x cm.
(5)^2+(x)^2=(12)
25+(x)^2=144
(x)^2=144-25
x=√119
x=10.9
Answer:
-13-9a
Step-by-step explanation:
