I always use Socratic see if that’ll help
To make this problem easier you could make the denominators equal to combine the 2 bills to see how of his paycheck is being used already. to 2/7 = 6/21 and 1/3=7/21 so with 6/21 and 7/21 you can combine them and you have 13/21 is used on bills so 21/21(which represents the whole paycheck) - 13/21 =8/21 so 8/21 is what is left his paycheck to spend write this as a decimal by dividing and you will have the percentage that he has left so 8/21 = .38 so he can spend approximately 38% of his check on games and 63dollars * .38 is about 24dollars 63*.38 =24(approximately) you divide 8/21 and get an exact answer.
Answer:
You would expect 807 babies to weigh between 3 and 6 pounds.
Step-by-step explanation:
We are given that
Mean,
pounds
Standard deviation,
pounds
n=1500
We have to find how many would you expect to weigh between 3 and 6 pounds.
The weights for newborn babies is approximately normally distributed.
Now,
Number of newborn babies expect to weigh between 3 and 6 pounds
=
Answer:
-3x^2-21x+24
Step-by-step explanation:
Kindly separate the answer choices: (x - 4), (x + 1), (x + 4) , (x - 1). The trinomial is thus -3x^2-21x+24, which can be factored as follows: -3(x^2 + 7x - 8)
Then we have -3x^2-21x+24 = -3(x^2 + 7x - 8), which factors further into:
-3(x + 8)(x -1) and so we conclude that the only binomial that is a factor of
-3x^2-21x+24 is (x - 1).
Answer:
probability of picking a yellow =0.4706
a blue or green = 0.2941
an orange = 0 ( there is no orange bag)
