Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
Seems like you are an imposter ;). This is Middle School math.
Anyways...
Answer:
x>6
Step-by-step explanation:
-4x-12<12
Add 12 on both sides.
-4x<24
Divide both sides by -4 to isolate x. Remember that if you are dividing by a negative, flip the sign!
x>6
Hope this helps!
Answer:
B = 48
Step-by-step explanation:
You are given that the two vertical lines are parallel. That means that the alternate interior angles are equal (they form a Z shape).
So the given is that A = B
A = 5x - 12
B = 2x + 24
Solution
5x - 12 = 2x + 24
5x - 12 = 2x + 24 + 12
5x = 2x + 36
5x - 2x = 36
3x = 36
x = 36/3
x = 12
================
B is
B = 2x + 24
B = 2*12 + 24
B = 24 + 24
B = 48
Answer:63
Step-by-step explanation:
