Let f be the fathers age and let s be the sons age
f = 60 s = 30
when f = 45
s = 15 which is only a third if his fathers age
when f = 40
s = 10 which is a quarter of his fathers age
therefore when his father was 4 times his age, the son was 10
Answer: -11 divided by 4 , 11 divided by -4 , -11/4 , 11/-4 ,
Step-by-step explanation:
I got it right on iready
s1+s2>s3 where s1 and s2 are the 2 smaller sides
Choice C is the only 1 that fits
7+13 >18
Answer:
A 3^4 * 3^-4 / 3^6
C 1 / 3^6
Step-by-step explanation:
( 3^2 * 3^-2)
------------------- all the the power of 2
3^3
First simplify the numerator
We know a^b* a^c = a^(b*c)
( 3^(2+-2))
------------------- all to the power of 2
3^3
( 3^(0))
------------------- all to the power of 2
3^3
( 3^(0))
------------------- all to the power of 2
3^3
We know a^b/ a^c = a^(b-c)
3^(0-3) all to the power of 2
3^-3 all to the power of 2
3^-3 ^2
We know that a^b^c = a^(b*c)
3^(-3*2)
3^ -6
We know the negative exponent takes if from the numerator to the denominator
1 / 3^6
The other correct choice is A
3^4 * 3^-4 = 3^0 which is 1
1/3^6 is the same answer
